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Mamont248 [21]
3 years ago
9

An unknown material has a mass

Physics
2 answers:
atroni [7]3 years ago
4 0

Answer: 1896.55J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1320 joules

Mass of material = 5.61kg

C = ? (let unknown value be Z)

Φ = 0.124°C

Then, Q = MCΦ

1320J = 5.61kg x Z x 0.124°C

1320J = 0.696kg°C x Z

Z = (1320J / 0.696kg°C)

Z = 1896.55 J/kg°C

Thus, the specific heat of the material is 1896.55J/kg°C

torisob [31]3 years ago
3 0

Answer:

1897.53J/Kg°C

Explanation:

Data obtained from the question include:

M (mass of material) = 5.61 kg

ΔT ( change in temperature) = 0.124°C

Q ( heat) = 1320 J

C (specific heat capacity of the material) =?

Using the formula Q = MCΔT, the specific heat capacity of the material can be obtained as follow:

Q = MCΔT

C = Q / MΔT

C = 1320J/ (5.61 kg x 0.124°C)

C = 1897.53J/Kg°C

Therefore, the specific heat capacity of the material is 1897.53J/Kg°C

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Find the volume of the irregular object a marble
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By using Displacement method we can find volume of irregular object like marble.

<h3>What is displacement method?</h3>

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Lastly , calculate the density by dividing the mass by the volume.

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2 years ago
What effect does the vertical acceleration have on the horizontal velocity of the projectile?
KengaRu [80]
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None, if air resistance is ignored.

Explanation:
At any instant, the projectile has vertical and horizontal components of velocity.
Vertical acceleration due to gravity affects the vertical velocity by accelerating the object toward the center of the earth, and by decreasing the upward vertical velocity.. 
The horizontal component of velocity makes the object travel horizontally as long as the projectile is airborne.
Thsi discussion assumes that air resistance is ignored.
3 0
3 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
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