As AL2006 correctly pointed out the formula is 1/2 kx^2. I was thinking of force and work is the integral of force over the distance applied. So now

and

Given terms :
- time (t) = 90 minutes = 1.5 hour
As we know, Distance covered is equal to :
Answer:
The acceleration of the refrigerator is 
Explanation:
The expression of the equation of the net force acting on the refrigerator is as follows;
F-f= ma
Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.
It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.
Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.
993 - 973 = (355)a
20 = 355 a

Therefore, the acceleration of the refrigerator is
.
Answer:
0.2631 N/C
Explanation:
Given that:
The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m
The radius of the thick wire r' = 0.55 mm = 0.55 × 10⁻³ m
The numbers of electrons passing through B, N = 6.0 × 10¹⁸ electrons
Electron mobility μ = 6.0 x 10-4 (m/s)/(N/C)
= 0.0006
The number of electron flow per second is calculated as follows:




The magnitude of the electric field is:
E = 
E = 
E = 
E = 0.2631 N/C
Answer:
10,600 m
Explanation:
Use range equation:
R = v₀² sin(2θ) / g
R = (433.0 m/s)² sin(2 × 64.8°) / (9.8 m/s²)
R = 14,700 m
The range is shortened by 28.1%.
0.719R = 10,600 m