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Mamont248 [21]
3 years ago
9

An unknown material has a mass

Physics
2 answers:
atroni [7]3 years ago
4 0

Answer: 1896.55J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1320 joules

Mass of material = 5.61kg

C = ? (let unknown value be Z)

Φ = 0.124°C

Then, Q = MCΦ

1320J = 5.61kg x Z x 0.124°C

1320J = 0.696kg°C x Z

Z = (1320J / 0.696kg°C)

Z = 1896.55 J/kg°C

Thus, the specific heat of the material is 1896.55J/kg°C

torisob [31]3 years ago
3 0

Answer:

1897.53J/Kg°C

Explanation:

Data obtained from the question include:

M (mass of material) = 5.61 kg

ΔT ( change in temperature) = 0.124°C

Q ( heat) = 1320 J

C (specific heat capacity of the material) =?

Using the formula Q = MCΔT, the specific heat capacity of the material can be obtained as follow:

Q = MCΔT

C = Q / MΔT

C = 1320J/ (5.61 kg x 0.124°C)

C = 1897.53J/Kg°C

Therefore, the specific heat capacity of the material is 1897.53J/Kg°C

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a car travels east with a velocity of 80 km/h for 90 minutes how far did the car travel (show your work)
olga55 [171]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Given terms :

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As we know, Distance covered is equal to :

  • velocity \times time

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3 years ago
You're having a hard time pushing a refrigerator across the kitchen floor. The force of your own push is 993 N. The force of fri
Helen [10]

Answer:

The acceleration of the refrigerator is a= 0.056 ms^{-2}

Explanation:

The expression of the equation of the net force acting on the refrigerator is as follows;

F-f= ma

Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.

It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.

Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.

993 - 973 = (355)a

20 = 355 a

a= 0.056 ms^{-2}

Therefore, the acceleration of the refrigerator is a= 0.056 ms^{-2}.

6 0
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The radius of the thinner wire is 0.22 mm and the radius of the thick wire is 0.55 mm. There are 4.0 x 1028 mobile electrons per
Natasha_Volkova [10]

Answer:

0.2631 N/C

Explanation:

Given that:

The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m

The radius of the thick wire  r' = 0.55 mm = 0.55 × 10⁻³ m

The numbers of electrons passing through B, N = 6.0  × 10¹⁸ electrons

Electron mobility  μ =  6.0 x 10-4 (m/s)/(N/C)

= 0.0006

The number of electron flow per second is calculated as follows:

I = \frac{q}{t}

I = \frac{Ne}{t}

I = \frac{6*10^{18}(1.6*10^{-18})C}{1 \ s}

I = 0.96 \ A

The magnitude of the electric field is:

E = \frac{I}{ \mu n eA}

E = \frac{I}{ \mu n e(\pi r^2)}

E = \frac{0.96}{(0.0006 m/s N/C ) (4*10^{28})(1.6*10^{-19}C)(0.55*10^{-3}m)^2}

E = 0.2631 N/C

8 0
3 years ago
A projectile is fired at 0=433.0 m/s
White raven [17]

Answer:

10,600 m

Explanation:

Use range equation:

R = v₀² sin(2θ) / g

R = (433.0 m/s)² sin(2 × 64.8°) / (9.8 m/s²)

R = 14,700 m

The range is shortened by 28.1%.

0.719R = 10,600 m

5 0
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