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3 years ago

An object on a spring whose constant is 30. N/m

Physics

1 answer:

MrRa [10]3 years ago

3 0

The mass of the object is 0.0076 kg

Explanation:

The frequency of a mass-spring system (simple harmonic motion) is given by

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

where

f is the frequency

k is the spring constant

m is the mass

For the mass-spring system in this problem, we know:

k = 30 N/m is the spring constant

f = 10 Hz is the frequency

Solving the equation for m, we find the mass:

$m=\frac{k}{(2\pi f)^2}=\frac{30}{(2\pi (10))^2}=0.0076 kg$

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Explanation:

The electric field equation of a electromagnetic wave is given by:

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For the magnetic field we have the next equation:

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$B_{max}=1.17*10^{-8}T$

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I hope it helps you!

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