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Free_Kalibri [48]
4 years ago
13

What’s the difference between medium-range training and LSD training? 2. What are the benefits of the starter phase of a fitness

program?
Physics
2 answers:
viktelen [127]4 years ago
8 0

Answer:

Explanation:

Medium range training in which the the work period is over top by lactic acid energy system. The time period is between 10 and 60 seconds.

This training focuses on developing a tolerant nature of lactic acid and to maintain high intensity output in performers.

Where as LSD or long slow distance comes in cycling or running and is done to improve cardiovascular function and capacity of skeletal muscle.

The benefits of starter phase of fitness program :

1- Fitness program is best for your health.

2- Physical activity helps to keep you away from chronic diseases.

3- It helps to increase the metabolism activity in your body and helps in better sleep and keep your body active.

NemiM [27]4 years ago
7 0

1. LSD (or long slow distance) training, also known as a continuous training,  involves performing an activity, such as jogging, cycling or swimming, nonstop for a period of time. This training is targeted for health-related improvements and is often required before engaging to more demanding, aerobic methods like fartlek. Medium-range on the other hand, is where the work period is dominated by the lactic acid energy system. This occurs either when the work period  is between 10 and 60 seconds or when the work-to-rest ratio is 1:2 or 1:3. The aim of medium-interval training is  to develop tolerance of lactic acid.

2. The starter phase allows the body to get used to the idea of exercise, avoid soreness and injury, and to experiment until you find the program that works best for you.

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baptist walked 420 m in 17.5 min. what is his average speed in m/min? What is his average speed in m/s? (Hint: There are 60 s in
yulyashka [42]

Answer:

Average speed is 24 m/min

in another unit is is 0.4 m/s

Explanation:

As we know that the average speed is the ratio of total distance covered and total time

so here we know that total distance moved by the baptist is

d = 420 m

total time taken by it is given as

t = 17.5 min

so average speed is given as

v = \frac{d}{t}

v = \frac{420}{17.5} m/min

v = 24 m/min

now we have to find the speed in m/s unit also

so we have

v = \frac{24}{60} m/s

v = 0.4 m/s

8 0
3 years ago
A cylindrical specimen of a nickel alloy having
tia_tia [17]

Answer:

L = 0.475 m = 475 mm = 18.7 inches

Explanation:

A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa and an original diameter of 10.2 mm (0.40 in.) will experience only elastic deformation when a tensile load of 8900 N (2000 lb ) is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is 0.25 mm (0.010 in).

E = 207 GPa = 207*10⁹ Pa

D = 10.2 mm = 0.0102 m

P = 8900 N

ΔL = 0.25 mm = 2.5*10⁻⁴ m

L = ?

We can use the Equation of the Hooke's Law

ΔL = P*L / (A*E)    ⇒   L = ΔL*A*E / P

⇒   L = (2.5*10⁻⁴ m)*(π*(0.0102 m)²*0.25)*(207*10⁹ Pa) / (8900 N)

⇒   L = 0.475 m = 475 mm = 18.7 inches

7 0
4 years ago
Please helpp this is due in 10 minutes?!!!!
Sati [7]

Answer:

1. at the top of the coaster.

2. at the bottom of the coaster.

3. when the car is moving

4. when the car is moving

Explanation:

there is the most amount if potential energy at the top, and the keast at the bottom.

5 0
3 years ago
An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder
castortr0y [4]

Answer:

Explanation:

Weight of the ladder is 355N

WL = 355N

The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

Weight of firefighters is 870N

Wf = 870N

The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted  by the wall

N2 is the normal force exerted  by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

N₂ = 1225 N

This the normal force exerted by the ground on the wall.

Now to get N₁, let take moment about point A

So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.

ΣMa = 0

Clockwise moment is equal to anti-clockwise moment

Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

5 0
3 years ago
Calculate momentum- what is the momentum of the wooden ball after the collision?
Serga [27]

Answer:

-32

Explanation:

8 0
3 years ago
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