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Free_Kalibri [48]
4 years ago
13

What’s the difference between medium-range training and LSD training? 2. What are the benefits of the starter phase of a fitness

program?
Physics
2 answers:
viktelen [127]4 years ago
8 0

Answer:

Explanation:

Medium range training in which the the work period is over top by lactic acid energy system. The time period is between 10 and 60 seconds.

This training focuses on developing a tolerant nature of lactic acid and to maintain high intensity output in performers.

Where as LSD or long slow distance comes in cycling or running and is done to improve cardiovascular function and capacity of skeletal muscle.

The benefits of starter phase of fitness program :

1- Fitness program is best for your health.

2- Physical activity helps to keep you away from chronic diseases.

3- It helps to increase the metabolism activity in your body and helps in better sleep and keep your body active.

NemiM [27]4 years ago
7 0

1. LSD (or long slow distance) training, also known as a continuous training,  involves performing an activity, such as jogging, cycling or swimming, nonstop for a period of time. This training is targeted for health-related improvements and is often required before engaging to more demanding, aerobic methods like fartlek. Medium-range on the other hand, is where the work period is dominated by the lactic acid energy system. This occurs either when the work period  is between 10 and 60 seconds or when the work-to-rest ratio is 1:2 or 1:3. The aim of medium-interval training is  to develop tolerance of lactic acid.

2. The starter phase allows the body to get used to the idea of exercise, avoid soreness and injury, and to experiment until you find the program that works best for you.

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A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway
vesna_86 [32]

Answer:

Average velocity = 1.69 m/s

Average speed = 5.09 m/s

Explanation:

Given that

Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.

As we know that

Average velocity = Displacement / Total time

Average speed  = Total distance / Total time

Average velocity:

  Average velocity = Displacement / Total time

Total displacement = 37 - 18.5 = 18.5 m

Total time = 9.1 + 1.8 =10.9 s

Average velocity = Displacement / Total time

Average velocity = 18.5 / 10.9

Average velocity = 1.69 m/s

Average speed:

  Average speed = Total distance/ Total time

Total distance = 37 + 18.5 = 55.5 m

Total time = 9.1 + 1.8 =10.9 s

Average speed = Total distance/ Total time

Average speed = 55.5 / 10.9

Average speed = 5.09 m/s

3 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
You drop a basketball (Mass = 0.5 kg) and a medicine ball (mass = 5 kg) from the window of the leaning tower of Pisa. Assuming t
erastova [34]
The medicine ball wall hit the ground faster, if that makes sense to you
4 0
3 years ago
It takes five hours to drive from Fort Worth to Midland, which is a distance of 300 miles. What
Shkiper50 [21]

Answer:

60

Explanation:

(hint: speed = distance/time)

8 0
3 years ago
A baseball was hit and reached its maximum height in 3.00s. Find (a) its initial velocity; (b) the height it reaches.[29.4 m/s;
kicyunya [14]

Answer:

u= 29.43 m/s

h=44.14 m

Explanation:

Given that

t= 3 s

We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)

Initial velocity  = u

Final velocity ,v= 0 (At maximum height)

We know v = u +a t

v=final velocity

u=initial velocity

a=Acceleration

Now by putting the values in the above equation

0 = u - 9.81 x 3

u= 29.43 m/s

The maximum height h is given as

v² = u ² -  2 g h

0² = 29.43 ² - 2 x 9.81 x h

h=\dfrac{29.43^2}{2\times 9.81}\ m

h=44.14 m

4 0
4 years ago
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