Answer:
A.
Explanation:
momentum depends on weight and speed
Answer;
Q = 359.2-J
Explanation;
Given that;
Constants for mercury at 1 atm
Heat capacity of Hg(l) is 28.0 J/(mol*K)
melting point is 234.32 K
Enthalpy of fusion is 2.29 kJ/mol
17.7-g Hg / 200.6g/mol = 0.0882 mol Hg;
°C + 273 = 298 K;
2.29-kJ/mol = 2290-J/mol
Q = (m x ΔT x Cp) + (m x Hf)
Q = 0.0882-mol x (298 - 234.32) x 28.0-J/mol*K) + (0.0882-mol x 2290-J/mol)
Q = 157.26-J + 201.978-J
Q = 359.2-J
Q=359-J (3 sig fig allowed due to 17.7-g given in problem)
Advantages
-Fluorescent bulbs are more efficient than filament bulbs
-They are cheaper to use as they consume less electricity
-Lasts longer
-Since it consumes less electricity, less electricity needs to be produced, so less fossil fuels needs to be burnt so less harm to the environment.
Disadvantages
-More expensive to buy
-Shortened life span if turned off and on very frequently.
-Disposal a problem because of mercury vapour.
I hope this helps!
please mark brainliest❤️
Answer:
6862.96871 seconds
Explanation:
M = Mass of Planet
G = Gravitational constant
r = Radius
= Density
T = Rotation period
In this system the gravitational force will balance the centripetal force
.
Hence, proved
The rotation period of the astronomical object is 6862.96871 seconds
Answer:
The capacitor will charge
Explanation:
When the capacitor is connected to the circuit containing the battery and the resistor, charges (electrons) will start flowing through the circuit, pushed by the electromotive force produced by the battery. In particular:
- electrons will flow from the negative terminal of the battery to one plate of the capacitor
- electrons will flow from the other plate of the capacitor to the positive terminal fo the battery
(It's important to keep in mind that the electrons never cross the gap between the plates of the capacitor.)
Therefore, negative charge will accumulate on one plate of the capacitor and positive charge will accumulate on the other plate: and so, there will be an increasing potential difference across the plates of the capacitor. Due to this increasing potential difference, it will become more and more difficult for the battery to "push" electrons on the negative plate (and to remove them from the other plates), so the current in the circuit will keep decreasing.
The process stops when the potential difference across the gap of the capacitor is equal to the e.m.f. of the battery: at this point, there is no more current in the circuit, and the capacitor is said to be fully charged.
