Answer:
166 torr
Explanation:
Let’s call ethane Component 1 and propane Component 2.
According to Raoult’s Law,
where
p₁ and p₂ are the vapour pressures of the components above the solution
χ₁ and χ₂ are the mole fractions of the components
p₁° and p₂° are the vapour pressures of the pure components.
Data:
p₁° = 304 torr
p₂° = 27 torr
n₁ = n₂
1. Calculate the mole fraction of each component
χ₁ = n₁/(n₁ + n₂)
χ₁ = n₁/n₁ + n₁)
χ₁ = n₁/(2n₁)
χ₁ = ½
χ₁ = 0.0.5
χ₂ = 1- χ₁ = 1- 0.5 = 0.5
2. Calculate the vapour pressure of the mixture
Answer: C. A force applied to the cart pushing or pulling it forward
Explanation: (I hope this is correct)
Answer:
Explanation has been given below
Explanation:
- In diaxial conformation of cis-1,3-disubstituted cyclohexane, 4 gauche-butane interactions along with syn-diaxial interaction are present. Hence it readily gets converted to diequitorial conformation where no such gauche-butane interaction is present
- In two possible conformations of trans-1,3-disubstituted cyclohexane, 2 gauche-butane interactions are present in each of them.
- Hence cis-1,3-disubstituted cyclohexane exists almost exclusively in diequitorial form. But trans-1,3-disubstituted cyclohexane has no such option.
- Trans-1,3-disubstituted cyclohexane experiences gauche butane interaction in each of the two conformations.
- Therefore cis-1,3-disubstituted cyclohexane is more stable than trans conformation
<span>B. The ignition point for a given fuel is met.</span>
Answer:
C) The puck gradually slows down because friction would be acting on it.
Explanation:
It would be C because the puck would be scraping the ice and when it's scraping it slowly losses its speed because the ground is pushing it lightly
Hoped that helped :/