Answer : The mass of calcium chloride is, 116.84 grams
Solution : Given,
Molar mass of calcium chloride, 
= 110.98 g/mole
Number of molecules of calcium chloride = 
As we know that,
1 mole of calcium chloride contains 
molecules of calcium chloride
or,
1 mole of calcium chloride contains 110.98 grams of calcium chloride
Or, we can say that
As, molecules of calcium chloride present in 110.98 grams of calcium chloride
So, molecules of calcium chloride present in 
of calcium chloride
Therefore, the mass of calcium chloride is, 116.84 grams
Answer:
brainly
Explanation:
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Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g
