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DerKrebs [107]
3 years ago
7

You're explaining to your client that using electronic documents and signatures simplifies the home buying process. Your client

is skeptical about these signatures. You describe the Uniform Electronic Transactions ACT (UETA) and tell your client?
Physics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer: State laws take precedence over UETA

Explanation: The UETA is an attempt to standardize acceptance of electronic documents and signatures, but state laws govern the use of these electronic items.

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A football player kicks a 0.94 kg football with a force of 2.4 N. Calculate the acceleration of the football as the player kicks
svlad2 [7]
The acceleration of the football is 2.6 m/s2
5 0
3 years ago
Read 2 more answers
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
3 years ago
A cantilever beam with a width b=100 mm and depth h=150 mm has a length L=2 m and is subjected to a point load P =500 N at B. Ca
DerKrebs [107]

Answer:

Explanation:

Given that:

width b=100mm

depth h=150 mm

length L=2 m =200mm

point load P =500 N

Calculate moment of inertia

I=\frac{bh^3}{12} \\\\=\frac{100 \times 150^3}{12} \\\\=28125000\ m m^4

Point C is subjected to bending moment

Calculate the bending moment of point C

M = P x 1.5

= 500 x 1.5

= 750 N.m

M = 750 × 10³ N.mm

Calculate bending stress at point C

\sigma=\frac{M.y}{I} \\\\=\frac{(750\times10^3)(25)}{28125000} \\\\=0.0667 \ MPa\\\\ \sigma =666.67\ kPa

Calculate the first moment of area below point C

Q=A \bar y\\\\=(50 \times 100)(25 +\frac{50}{2} )\\\\Q=250000\ mm

Now calculate shear stress at point C

=\frac{FQ}{It}

=\frac{500*250000}{28125000*100} \\\\=0.0444\ MPa\\\\=44.4\ KPa

Calculate the principal stress at point C

\sigma_{1,2}=\frac{\sigma_x+\sigma_y}{2} \pm\sqrt{(\frac{\sigma_x-\sigma_y}{2} ) + (\tau)^2} \\\\=\frac{666.67+0}{2} \pm\sqrt{(\frac{666.67-0}{2} )^2 \pm(44.44)^2} \ [ \sigma_y=0]\\\\=333.33\pm336.28\\\\ \sigma_1=333.33+336.28\\=669.61KPa\\\\\sigma_2=333.33-336.28\\=-2.95KPa

Calculate the maximum shear stress at piont C

\tau=\frac{\sigma_1-\sigma_2}{2}\\\\=\frac{669.61-(-2.95)}{2}  \\\\=336.28KPa

6 0
3 years ago
A car travels 40 miles in 2 hours. If the car travels another 60 moles how long will it take to travel
Kisachek [45]

Answer:

<u><em>3 hours</em></u>

Explanation:

If the car takes 2 hours to go 40 miles, then the car can go 20 miles in 1 hour. Since the car is going 60 miles, it will take 3 hours.

Hope that makes sense :)

8 0
4 years ago
Read 2 more answers
Match the following items.
Ray Of Light [21]

Answer:

Je ne Sachez que Qu’est-ce que le

8 0
3 years ago
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