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mr_godi [17]
3 years ago
9

Select the compound in which chlorine is assigned the oxidation number +5.

Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0
The answer is d.
Hope this helps plz give brainliest!
inn [45]3 years ago
4 0

Answer:

The answer is d

Explanation:

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The units of density are kg/m2. If the density of a liquid is 760.0 kg/m' what is the specific volume? a) 1.316 x 10 m2/kg b) 1.
zlopas [31]

Answer:

The correct answer is: 1.316 . 10⁻³ m³/kg.

Explanation:

The density (ρ) of a substance is the ratio of its <em>mass (m)</em> to its <em>volume (V)</em>. At constant temperature and pressure, its value is constant and it is an intrinsic property of materials. The units of density are kg/m³.

\rho = \frac{m}{V}

The specific volume (ν) of a substance is the ratio of its <em>mass</em> to its <em>volume</em>. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

\nu = \frac{V}{m}=\frac{1}{\rho }

Given we know the density of the liquid, we can use this relationship to find out its specific volume:

\nu =\frac{1}{\rho }=\frac{1}{760.0kg/m^{3} } =1.316 .10^{-3} m^{3} /kg

6 0
3 years ago
What are 5 responsibilities a citizen has in taking part in public affairs
zimovet [89]
1. To vote 
2. To abide by laws 
3. To contribute to society positively 
4. To be kind to people around you 
<span>5. To pass on the top four to your children and neighbors</span>
3 0
3 years ago
What is the molarity of a solution that contains 4.3 mol of acetic acid (C2H3O2) in 450. mL of solution?
lord [1]

Hey there !


Number of moles of solution: 4.3 moles

Volume in liters:

450.0 mL / 1000 => 0.45 L

Therefore:

Molarity = number of moles / volume of solution ( L)

Molarity = 4.3 / 0.45

=> 9.55 M

Hope that helps!

3 0
3 years ago
A fixed mass of a gas occupies 1000cm
Serhud [2]

Answer:

the pressure of gas is 100.0 the volume is 500.0

Explanation:

4 0
3 years ago
If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
USPshnik [31]

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = \frac{mass}{molar mass}  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = \frac{18.1}{143.2}   = 0.13moles

Number of moles of NH₃   = \frac{90.4}{17}   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

5 0
3 years ago
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