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mr_godi [17]
3 years ago
9

Select the compound in which chlorine is assigned the oxidation number +5.

Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0
The answer is d.
Hope this helps plz give brainliest!
inn [45]3 years ago
4 0

Answer:

The answer is d

Explanation:

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Which of the following is the first stage of aerobic respiration?
kvasek [131]

Answer:

glycolysis

Explanation:

The first stage of the aerobic and an-aerobic respiration is glycolysis. In the glycolysis, the glucose molecule breaks down into two three carbon compound pyruvic acid. #answerwithquality #BAL

7 0
3 years ago
Draw two resonance forms for nitrosyl chloride, ONCl. Which one is better and why?
rusak2 [61]

Explanation:

this molecule does not exhibit any resonance, and even if it does, this structure would be the most viable since the net charge on all of the atoms are 0.

5 0
3 years ago
6969696969696969696696969696969+333333333x3333333333333
solniwko [45]

Answer:

my calculator said this

Explanation:

6.96969697E30

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4 0
3 years ago
When using the ideal gas constant value, R = 0.0821, in an ideal gas law calculation, the units of temperature may be expressed
vovangra [49]
The statement "When using the ideal gas constant value, R = 0.0821, in an ideal gas law calculation, the units of temperature may be expressed as degrees Celsius or <span>Kelvin" is false. It must be Kelvin only not celsius</span>
6 0
3 years ago
A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium
ozzi

Answer:

Percent yield = 57.8 %

Theoretical yield  = 11.781 g

Explanation:

Given data:

Mass of CaO produced = 6.81 g

Mass of CaCO₃ react = 20.7 g

Theoretical yield = ?

Percent yield = ?

Solution:

Chemical equation:

CaCO₃       →      CaO + CO₂

Number of moles of CaCO₃ :

Number of moles = mass/molar mass

Number of moles = 20.7 g/ 100.1 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of CaCO₃ with CaO.

                  CaCO₃        :           CaO

                       1              :              1

                      0.21         :           0.21

Theoretical yield of CaO:  

Mass = number of moles × molar mass

Mass = 0.21 mol × 56.1 g/mol

Mass = 11.781 g

Percent yield:

Percent yield = ( actual yield / theoretical yield ) ×  100

Percent yield = (6.81 g/ 11.781 g) × 100

Percent yield = 57.8 %

8 0
3 years ago
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