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zmey [24]
3 years ago
8

Choose the correct answer. A circle is centered at the point (0,-2) and rotated about the x axis.

Mathematics
2 answers:
netineya [11]3 years ago
7 0

Answer:

B is the answer ok bro bye

Zarrin [17]3 years ago
4 0

Answer:

see attached.

Step-by-step explanation:

when a circle is located at centre of point (0,-2)

and rotated at x-axis.

it would look like a Torus

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If m<9=130°, what is m<4?
nikklg [1K]

From the diagram provided, the two lines that are left and right of each other are parallel and are cut by a transversal. That means,

\begin{gathered} \angle9=\angle5\text{ (corresponding angles are equal)} \\ \text{Similarly,} \\ \angle8=\angle4\text{ (corresponding angles are equal)} \end{gathered}

If angle 9 equals 130, then angle 8 equals,

\begin{gathered} 130+\angle8=180\text{ (angles on a straight line sum up to 180)} \\ \angle8=180-130 \\ \angle8=50 \end{gathered}

If angle 8 equals angle 4, then angle 4 equals 50 degrees

3 0
1 year ago
Which property is shown (5×3)+(5×9)=5×(3+9)
mote1985 [20]
Resolve to do so
5x3=15 
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8 0
3 years ago
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jeka57 [31]
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7 0
2 years ago
A newborn baby has 26,000,000,000 cells. An adult has about 1.9×10³ times as many as a newborn. About how many cells does an adu
Alenkinab [10]
*Hint* the ^ just means that the following numbers are powers like 1.9x10^3 is same as 1.9x10³


To figure this out just multiply 

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6 0
2 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
2 years ago
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