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saw5 [17]
3 years ago
12

Consider a wing mounted in the test-section of a subsonic wind tunnel. The velocity of the airflow is 160 ft/s, and the velocity

at a point on the wing is 293 ft/s.
If the test-section air temperature is 510°R and the flow velocity is increased to 450 ft/s, what is the pressure coefficient at the same point?


(Round the final answer to three decimal places.)
Engineering
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

A) To find the coefficient of pressure we will use

PC=1-(\frac{V}{v_{\alpha } } )^2

where

V=293 ft/s\\v_{\alpha } =160ft/s

insert values

PC=1-(293/160)^2=-2.353

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What is the standard half-cell potential for the oxidation of methane under acidic conditions? The reaction for methane is as fo
Yuri [45]

Answer:

The element that is oxidized is carbon.

Its oxidation state increased. It increased from -4 to +4

Explanation:

Oxidation is a process that involves increase in oxidation number.

The oxidation number of carbon in CH4 is -4

C + (1×4) = 0

C + 4 = 0

C = 0 - 4 = -4

The oxidation number of carbon in CO2 is +4

C + (2×-2) = 0

C - 4 = 0

C = 0+4 = 4

Increase in the oxidation number of carbon from -4 to +4 means carbon is oxidized

4 0
3 years ago
In the ______ phase of the organizational life cycle, the organization is usually very small and agile, focusing on new products
Vlad [161]

Answer:

Entrepreneurship

Explanation:

Different phases of  organizational life cycles can be observed depending on the stage of the company. These cycles are,

  • Entrepreneurship
  • Survival and Early Success
  • Sustained Success
  • Renewal (or Decline)

In the initial stage which is  Entrepreneurship Phase,  all of the founders take part in various activities, no formality is formed between founders and employees. Generally lots of ideas are present and company is actively searching to define correct market and products to focus on.

5 0
3 years ago
A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. Calculate the number of atoms in t
uysha [10]

Answer:288 pm

Explanation:

Number of atoms(s) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- whereas

For an FCC lattices √2a =4r =2d

Therefore d = a/√2a = 408pm/√2a= 288pm

I think with this step by step procedure the, the answer was clearly stated.

8 0
3 years ago
A closed vessel of volume 80 litres contain gas at a gauge pressure of 150 kPa. If the gas is compressed isothermally to half it
horsena [70]

Answer:

The resulting pressure is 300 kilopascals.

Explanation:

Let consider that gas within the closed vessel behaves ideally. By the equation of state for ideal gases, we construct the following relationship for the isothermal relationship:

P_{1}\cdot V_{1} = P_{2} \cdot V_{2} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in litres.

If we know that \frac{V_{1}}{V_{2}} = 2 and P_{1} = 150\,kPa, then the resulting pressure is:

P_{2} = P_{1}\times \frac{V_{1}}{V_{2}}

P_{2} = 300\,kPa

The resulting pressure is 300 kilopascals.

6 0
3 years ago
Section lines represent surfaces exposed by a cutting plane<br> a. True b. False
oksian1 [2.3K]

Answer:

these is very interesting question but I still know the answer is a. True

7 0
3 years ago
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