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Mkey [24]
3 years ago
7

An insulated piston–cylinder device initially contains 1 m3 of air at 120 kPa and 17°C. Air is now heated for 15 min by a 200-W

resistance heater placed inside the cylinder. The pressure of air is maintained constant during this process. Determine the entropy change of air, assuming: (a) constant specific heats. (b) variable specific heats.

Engineering
1 answer:
irakobra [83]3 years ago
4 0

Answer:

∆S1 = 0.5166kJ/K

∆S2 = 0.51826kJ/K

Explanation:

Check attachment for solution

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Write the definition of a function printLarger, which has two int parameters and returns nothing. The function prints the larger
vredina [299]

Answer:

  1. #include <iostream>
  2. using namespace std;
  3. void printLarger(int a, int b){
  4.    
  5.    if(a > b){
  6.        cout<<a;
  7.    }else{
  8.        cout<<b;
  9.    }
  10. }
  11. int main()
  12. {
  13.    printLarger(4, 5);
  14.    return 0;
  15. }

Explanation:

The solution code is written in C++.

Firstly define a function printLarger that has two parameters, a and b with both of them are integer type (Line 5). In the function, create an if condition to check if a bigger than b, print a to terminal (Line 7-8). Otherwise print b (Line 9-10).

In the main program, test the function by passing 4 and 5 as arguments (Line 16) and we shall get 5 printed.  

7 0
4 years ago
The motion of a particle is defined by the relation x = t3 – 6t2 + 9t + 3, where x and t are expressed in feet and seconds, resp
Semmy [17]

Answer:

a. t=3secs and t=1sec

position is -7ft,acceleration is 18fts⁻², total distance travelled is 120ft

Explanation:

the displacement is define as

x=t³-6t²+9t+3·

since we are giving the position as a function of time, the velocity is the derivative of the position,

v=dx/dt

v=d(t³-6t²+9t+3)/dt

recall for y=axⁿ the derivative

dy/dx=a*nxⁿ⁻¹ and the derivative of a constant is zero

hence

V=3t²-12t+9

for V=0,

equivalent to t²-4t+3

solving the quadratic equation, we arrive at

(t-3)(t-1)=0

either t=3 or t=1

hence,at 3secs and 1sec the velocity is zero.

To determine the position at t=5, we substitute t=5 into

t³-6t²+9t+3

(5)³-6(5)²+9(5)+3

125-180+45+3

-7ft

The position at t=5 is -7ft

To determine the acceleration, we differentiate the velocity

a=dv/dt

a=d(3t²-12t+9)/dt

a=6t-12

at t=5

a=6(5)-12

a=18fts⁻²

Next we determine the distance covered at t=5

velocity =total distance travelled/total time taken

velocity=3t²-12t+9

V=3(25)-12(5)+9

V=24ft/s

Hence total distance travelled in t=5 is

24*5=120ft

6 0
3 years ago
The arrival rate at a parking lot is 6 veh.min. Vehicles start arriving at 6:00PM and when the queue reaches 36 vehicles, servic
seraphim [82]

Answer:

Departure rate = 7.65 vehicle/min

Explanation:

See the attached file for the calculation.

5 0
3 years ago
A thin metal disk of mass m=2.00 x 10^-3 kg and radius R=2.20cm is attached at its center to a long fiber. When the disk is turn
topjm [15]

Answer:

k = 1.91 × 10^-5 N m rad^-1

Workings and Solution to this question can be viewed in the screenshot below:

6 0
3 years ago
Explain what a stress-concentration is and how it can be accounted for in the design and analysis of a structural component. Be
Mama L [17]

Answer:

Stress-concentration

        In the machine component the stress become concentrate at the point a particular point and due to this crack formation takes places and after some time some the machine component become fails.High stress concentration means high stress at that point.

It is very important in the design point of view because we have to find out where stress concentration is high and needs to take proper factor of safety to avoid the failure of the machine component.Generally at sharp corner,sudden change and complex shapes stress concentration is high.

3 0
3 years ago
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