Answer:
389.6 W/m²
Explanation:
The power radiated to the surroundings by the small hot surface, P = σεA(T₁⁴ - T₂⁴) where σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m²-K⁴, ε = emissivity = 0.8. T₁ = temperature of small hot surface = 430 K and T₂ = temperature of surroundings = 400 K
So, P = σεA(T₁⁴ - T₂⁴)
h = P/A = σε(T₁⁴ - T₂⁴)
Substituting the values of the variables into the equation, we have
h = 5.67 × 10⁻⁸ W/m²-K⁴ × 0.8 ((430 K )⁴ - (400 K)⁴)
h = 5.67 × 10⁻⁸ W/m²-K⁴ × 0.8 (34188010000 K⁴ - 25600000000 K⁴)
h = 5.67 × 10⁻⁸ W/m²-K⁴ × 0.8 × 8588010000K⁴
h = 38955213360 × 10⁻⁸ W/m²
h = 389.55213360 W/m²
h ≅ 389.6 W/m²
Maybe because of shipping costs and if you need to buy materials from a far place such as different international travels?
Answer:
r=0.228m
Explanation:
The equation that defines the states of a gas according to its thermodynamic properties is given by the general equation of ideal gases
PV=nRT
where
P=pressure =5bar=500.000Pa
V=volume
n=moles=10
R = universal constant for ideal gases = 8.31J / (K.mol)
T=temperature=80F=299.8K
solvig For V
V=(nRT)/P
we know that the volume of a sphere is
solving for r
![r=\sqrt[3]{ \frac{3 V}{4\pi } }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20V%7D%7B4%5Cpi%20%7D%20%7D)
solving
![r=\sqrt[3]{ \frac{3 (0.049)}{4\pi } }\\r=0.228m](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%280.049%29%7D%7B4%5Cpi%20%7D%20%7D%5C%5Cr%3D0.228m)
Answer: The normalized corrected value at 32.5 mm = 0.69 mV
Explanation:
Signal value V1 = 20.7 mV at
distance value = 29 mm and
V2 = 15.8 mV is measured at 32.5 mm.
It is necessary, therefore, to subtract off this background level from the data to obtain a valid measurement
V1 = 20.7 - 5.1 = 15.6 mV
V2 = 15.8 - 5.1 = 10.7mV
The normalized corrected value at 32.5 mm will be
Vn = V2/V1 since V1 is the maximum value
Vn = 10.7/15.6 = 0.69 mV
Answer:Just multiply 90 by itself 46 times
Explanation:
do it
