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Ede4ka [16]
3 years ago
6

Section lines represent surfaces exposed by a cutting plane a. True b. False

Engineering
1 answer:
oksian1 [2.3K]3 years ago
7 0

Answer:

these is very interesting question but I still know the answer is a. True

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The storage tanks are on a platform placed next to the building at the second-floor level. Based on the potential hazards, are t
LuckyWell [14K]

The should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

<h3>What are potential hazards?</h3>

Potential hazards refers to the active source for potential damage on a building, structure etc

It is important we know that the storage tanks are placed on a platform next to the building at the second-floor level but nothing beneath the tanks stands.

Hence, there should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

Read more about Potential hazards

<em>brainly.com/question/7310653</em>

5 0
2 years ago
A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft
grandymaker [24]

Answer:

peak-hour volume = 1890 veh/h

Explanation:

<u>Determine the peak-hour Volume </u>

Applying the equation below

Vp =  v / ( PHF * N * Fg * Fdp )  -------------- ( 1 )

where :

Vp = 1250

v ( peak - hour volume ) =  ?

PHF ( peak hour factor ) = 0.84

N  = 2 lanes per direction

Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1

Fdp = 0.90

<u>Back to equation 1 </u>

v = Vp (  PHF * N * Fg * Fdp )  

  = 1250 ( 0.84 * 2 * 1 * 0.90 )

  = 1890 veh/h

5 0
3 years ago
A 3-phase , 1MVA, 13.8kV/4160V, 60 Hz, transformer with Y-Delta winding connection is supplying a3-phase, 0.75 p.u. load on the
Tanya [424]

Answer:

a) 23.89 < -25.84 Ω

b) 31.38 < 25.84 A

c) 0.9323 leading

Explanation:

A) Calculate the load Impedance

current on load side = 0.75 p.u

power factor angle = 25.84

I_{load} = 0.75 < 25.84°

attached below is the remaining part of the solution

<u>B) Find the input current on the primary side in real units </u>

load current in primary = 31.38 < 25.84 A

<u>C) find the input power factor </u>

power factor = 0.9323 leading

<em></em>

<em>attached below is the detailed solution </em>

8 0
3 years ago
How do you remove a manual transmission?
Citrus2011 [14]

Answer:

Step 1

Elevate the front of the vehicle using the floor jack and support the vehicle with two jack stands. Make sure the vehicle is stable.

Step 2

Disengage all electrical components connected to the transmission. Indicate by marking the position of the drive shaft for its reinstallation. From the output shaft, remove the rear U joint. Jam the cloth to keep the liquid from dripping out of the extension housing.

Step 3

Loosen the shift linkages and the speedometer cable from the transmission manually. Place the transmission jack under the transmission, and then take a socket wrench and remove the support nut, the cross-member, and the rear support insulator from the rear engine. Support the engine with a jack stand and use the transmission jack to withdraw the transmission toward the rear of the vehicle.

Explanation:

4 0
4 years ago
Laws that protect businesses involve
mr_godi [17]
Laws that protect businesses involve contracts, employment law, intellectual property, real estate, bankruptcy, and many other areas of the law.
4 0
3 years ago
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