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Dmitry [639]
4 years ago
11

Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4

Chemistry
1 answer:
Aleksandr [31]4 years ago
7 0

The concentration of hydroxide ion is  5  \times 10^ − 14  M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

                          H C l O 4  ⇌  H +  +  C l O  4 -

Moreover, let's assume that  H C l O 4  is a strong acid and will fully dissociate.

Hence,

                              [ H + ]  =  0.20  M

Now, recall,  

                  K w  =  [ H + ] [ O H − ]  =  1.0  \times 10 ^− 14

Hence,

                  ⇒ [ O H − ]  =  K w  / [ H + ]  = 5  \times 10^ − 14  M.

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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
4 years ago
11. To make sure that your guests don't get food poisoning at Thanksgiving dinner, you decide to use a pop-up
ohaa [14]

Answer:

Do not use this exact photo please!

Explanation:

3 0
3 years ago
When polonium-210 emits an alpha particle, the child isotope has an atomic mass of
Sergeeva-Olga [200]

Answer: The child isotope has an atomic mass of 206.

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of an element is given as:   _Z^A\textrm{X}

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

General representation of alpha decay :

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha

_{84}^{210}\textrm{Po}\rightarrow_{82}^{206}\textrm{Pb}+_2^4\textrm{He}

8 0
3 years ago
Read 2 more answers
Addition of water to an alkyne gives a keto‑enol tautomer product. Draw an enol that is in equilibrium with the given ketone
Marrrta [24]

Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
  2. If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
  4. This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.

7 0
2 years ago
How many atoms in 4.75 moles of gold, au?
arsen [322]
<span>The number of atoms in 4.75 moles of gold (Au) is found using Avogadro's number, which is 6.022Ă—1023 mol-1. Determine the number of atoms by multiplying 4.75 moles by Avogadro's number. The number of atoms in 4.75 moles of gold is 2.8605172125000205e24.</span>
6 0
3 years ago
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