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Dmitry [639]
4 years ago
11

Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4

Chemistry
1 answer:
Aleksandr [31]4 years ago
7 0

The concentration of hydroxide ion is  5  \times 10^ − 14  M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

                          H C l O 4  ⇌  H +  +  C l O  4 -

Moreover, let's assume that  H C l O 4  is a strong acid and will fully dissociate.

Hence,

                              [ H + ]  =  0.20  M

Now, recall,  

                  K w  =  [ H + ] [ O H − ]  =  1.0  \times 10 ^− 14

Hence,

                  ⇒ [ O H − ]  =  K w  / [ H + ]  = 5  \times 10^ − 14  M.

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In a particular titration experiment a 30.0 ml sample of an unknown hcl solution required 25.0 ml of 0.200 m naoh for the end po
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The balanced equation for the acid base reaction is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
the number of NaOH moles reacted - 0.200 mol/L x 0.0250 L = 0.005 mol
according to molar ratio
number of NaOH moles reacted = number of HCl moles reacted 
therefore number of HCl moles - 0.005 mol 
volume of 30.0  mL contains 0.005 mol
therefore 1000 mL contains - 0.005 mol / 0.030 L = 0.167 M
concentration of HCl is 0.167 M
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