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3 years ago

1) Assertion: On Freely suspending a current carrying solenoid, it comes to rest in N-S direction just like a bar-magnet.

Physics

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

Explanation:

1. A solenoid is a coil which has many turns. When current flows through a solenoid, it behaves as an electromagnet. This behavior is due to the magnetic effect of an electric current thereby causing one end of the solenoid to behave as a north pole, while the other end as a south pole.The external influence of the earth's magnetism constrains the solenoid to come to rest in a N-S position just like a bar magnet.

2. The magnetic compass can be used to trace the alignments or patterns of the magnetic field around a current carrying wire. When current flows in a wire, it induces magnetic field around it. If the value of current is increased, the strength of the magnetic field would increase and vice versa. This shows that current is proportional to the strength of the magnetic field produced around the wire. Thus this causes a deflection of the compass appropriately, as the deflection of the compass is proportional to the strength of the field.

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What the heck is friction

Anuta_ua [19.1K]

Answer:

Explanation:

Friction is a force that makes an object slow down. Not speed up, cause it to move, or occurs in a vacuum. Friction is often caused by the surface an object is moving on.

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3 years ago

Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open

Basile [38]

The electrostatic energy stored in a capacitor with capacitance $C_0$ , with a voltage difference V applied to it, and without dielectric, is given by
$U_0 = \frac{1}{2} C_0 V^2$
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
$C_k = k C_0$
So, the energy stored now is
$U_k = \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2$

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
$\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}= k$

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3 years ago

10. A 12 kg load hangs from one end of a rope that passes over a small frictionless pulley. A 15 kg counterweight is suspended f

nekit [7.7K]

Answer:

Explanation:

6 0

3 years ago

The photoelectric effect tells us that __________.

Ivanshal [37]

It describes the process by which surface electron's are emitted from a metal when light is shined on it.
And it tells us that light at a higher intensity must contain more quanta of energy, known as protons.

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3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

6 0

3 years ago