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stira [4]
3 years ago
12

At a dock, a crane lifts a 2009 kg container 20 m, swings it out over the deck of a freighter, and lowers the container into the

hold of the freighter, which is 8 m below the level of the dock. The acceleration of gravity is 9.81 m/s 2 . Neglect friction losses. How much work is done by the crane on the container? Answer in units of kJ
Physics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

W = 157.5kJ

Explanation:

Assuming it moves the container at constant speed, the work done by the crane will be equal to the variation of the potential gratitational energy on the container:

Wc = \Delta E = m*g*(h2 - h1)  where h2= -8m  and  h1=0m

Wc = 157.5kJ

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Missing details: figure of the problem is attached.

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where:

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r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

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Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s

and r=1 mm=0.001 m

Using these data in the formula, we get:

\Delta P = 3200 Pa

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2 years ago
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Arte-miy333 [17]

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alukav5142 [94]

Answer:

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