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Advocard [28]
2 years ago
7

In which state of matter are water molecules measured as having the lowest temperature?

Physics
2 answers:
natali 33 [55]2 years ago
4 0
Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.
Ilia_Sergeevich [38]2 years ago
4 0

It had better be the liquid state.  That's the only state in which you'd HAVE any water molecules.

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What is difference between non uniform and uniform circular motion?
statuscvo [17]

Answer:

The object in a uniform motion covers same distances in an equal time period. Objects in a non-uniform motion cover dissimilar distances in an equal time period.

Explanation:

The speed of the object traveling in uniform motion is constant, the actual speed and the average speed of the moving body is same.

6 0
3 years ago
Which two surfaces would have the highest coefficient of friction?
scoray [572]
<span>1. sandpaper against wood. 
2. rubber mat against the floor of the shower stall.

</span><span># High coefficient of friction describes the degree of interaction between two surfaces. . A higher coefficient of friction indicates that two surfaces in contact have a greater resistance.</span>
5 0
3 years ago
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5. For the speaker in this circuit, the voltage across it is always proportional to the current through it. Find the maximum amo
rosijanka [135]

Answer:

speaker64

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34x

Explanation:

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4 0
3 years ago
Can someone help me answer this
netineya [11]

Answer: b is sedimentary. c is metamorphic. and a is igneous.

Explanation:

6 0
3 years ago
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The train passes point A with a speed of 30 m/s and begins to decrease its speed at a constant rate of at = - 0.25 m/s^2. Determ
prisoha [69]

Explanation:

At point B, the velocity speed of the train is as follows.

          \nu^{2}_{B} = \nu^{2}_{A} + 2a_{t} (s_{B} - s_{A})

                           = (30)^{2} + 2(-0.25(412 - 0))

                           = 26.34 m/s

Now, we will calculate the first derivative of the equation of train.

          y = 200 e^{\frac{x}{1000}}

      \frac{dy}{dx} = 0.2 e^{\frac{x}{1000}}

Now, second derivative of the train is calculated as follows.

         \frac{dy}{dx} = 0.2 e^{\frac{x}{1000}}      

       \frac{d^{2}y}{dx^{2}} = 0.2 (10^{-3}) e^{\frac{x}{1000}}    

Radius of curvature of the train is as follows.  

   \rho = \frac{[1 + (\frac{dy}{dx})^{2}]^{\frac{3}{2}}}{\frac{d^{2}y}{dx^{2}}}

               = \frac{[1 + 0.2e^{\frac{400}{1000}}^{2}]^{\frac{3}{2}}}{0.2(10^{-3})e^{\frac{400}{1000}}}

              = 3808.96 m

Now, we will calculate the normal component of the train as follows.

            a_{n} = \frac{\nu^{2}_{B}}{\rho}

                        = \frac{(26.34)^{2}}{3808.96}

                        = 0.1822 m/s^{2}

The magnitude of acceleration of train is calculated as follows.

            a = \sqrt{(a_{t})^{2} + (a_{n})^{2}}

               = \sqrt{(-0.25)^{2} + (0.1822)^{2}}

              = 0.309 m/s^{2}

Thus, we can conclude that magnitude of the acceleration of the train when it reaches point B, where sAB = 412 m is 0.309 m/s^{2}.

6 0
3 years ago
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