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mrs_skeptik [129]
3 years ago
14

WhT DO FILM PRODUTION SAY WHEN REMOVING GREEN AND BLUE SCREENS.

Engineering
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

green im doing this for points 2123

Explanation:

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Which is the required type of fire extinguisher for standard naval vessels
Bess [88]

Answer:

Mentioned below are the required types of fire extinguishers for standard naval vessels:

  1. Soda Acid Fire Extinguisher
  2. Water Extinguisher
  3. Foam Extinguisher – Chemical and Mechanical
  4. Carbon Dioxide Extinguisher
  5. Dry Powder Extinguisher

Explanation:

A fire extinguisher is a functioning fire insurance gadget used to douse or control little fires, regularly in crisis circumstances. It isn't planned for use on a wild fire, for example, one which has arrived at the roof, jeopardizes the client (i.e., no way out course, smoke, blast danger, and so on.), or in any case requires the mastery of a fire unit. Ordinarily, a fire extinguisher comprises of a hand-held barrel shaped weight vessel containing an operator that can be released to stifle a fire. Fire extinguishers made with non-round and hollow weight vessels likewise exist however are less normal.

A naval vessel is a military boat (or in some cases pontoon, contingent upon arrangement) utilized by a naval force. Naval boats are separated from non military personnel delivers by development and reason. By and large, naval boats are harm versatile and furnished with weapon frameworks, however combat hardware on troop transports is light or non-existent. Naval vessel is planned fundamentally for naval fighting are named warships, rather than help (assistant boats) or shipyard activities.

3 0
3 years ago
which of the following statements are true about client-side DNS? (Choose all that apply). a. If an APIPA address is assigned, t
Brums [2.3K]

The statements which are true about client-side DNS include all of the following;

B. Client-side DNS should be configured to point towards the DNS server that is authoritative for the domain that client wants to join.

C. Check out DNS settings using the NSLookup command.

D. Check out DNS settings using the DIG command.

E. The cache.dns file has the IP addresses of the 13 root DNS servers.

B. If a web site can be reached by IP address and not by host name, then DNS or the Hosts file would be the problem.

<h3>What is a DNS server?</h3>

In Computer technology, a DNS server can be defined as a type of server that is designed and developed to translate domain names into IP addresses, so as to allow end users access websites and other internet resources through a web browser.

This ultimately implies that, a DNS server simply refers to a type of server that is designed and developed to translate requests for domain names into IP addresses for end users.

Read more on a domain names here: brainly.com/question/19268299

#SPJ1

5 0
1 year ago
g A 30-m-diameter sedimentation basin has an average water depth of 3.0 m. It is treating 0.3 m3/s wastewater flow. Compute over
stepladder [879]

Answer:

The overflow rate is 4.24×10^-4 m/s.

The detention time is 7069.5 s

Explanation:

Overflow rate is given as volumetric flow rate ÷ area

volumetric flow rate = 0.3 m^3/s

area = πd^2/4 = 3.142×30^2/4 = 706.95 m^2

Overflow rate = 0.3 m^3/s ÷ 706.95 m^2 = 4.24×10^-4 m/s

Detention time = volume ÷ volumetric flow rate

volume = area × depth = 706.95 m^2 × 3 m = 2120.85 m^3

Detention time = 2120.85 m^3 ÷ 0.3 m^3/s = 7069.5 s

6 0
3 years ago
A particular electromagnetic wave travelling in vacuum is detected to have a frequency of 3 × 10 12 Hz. How much time will it ta
irina1246 [14]

3×10^-12 seconds

Explanation:

T=1/f

7 0
2 years ago
Refrigerant-134a enters the expansion valve of a refrigeration system at 120 psia as a saturated liquid and leaves at 20 psia. D
Shkiper50 [21]

Solution :

$P_1 = 120 \ psia$

$P_2 = 20 \ psia$

Using the data table for refrigerant-134a at P = 120 psia

$h_1=h_f=40.8365 \ Btu/lbm$

$u_1=u_f=40.5485 \ Btu/lbm$

$T_{sat}=87.745^\circ  F$

∴ $h_2=h_1=40.8365 \ Btu/lbm$

For pressure, P = 20 psia

$h_{2f} = 11.445 \ Btu/lbm$

$h_{2g} = 102.73 \ Btu/lbm$

$u_{2f} = 11.401 \ Btu/lbm$

$u_{2g} = 94.3 \ Btu/lbm$

$T_2=T_{sat}=-2.43^\circ  F$

Change in temperature, $\Delta T = T_2-T_1$

                                         $\Delta T = -2.43-87.745$

                                           $\Delta T=-90.175^\circ  F$

Now we find the quality,

$h_2=h_f+x_2(h_g-h_f)$

$40.8365=11.445+x_2(91.282)$

$x_2=0.32198$

The final energy,

$u_2=u_f+x_2.u_{fg}$

   $=11.401+0.32198(82.898)$

   $=38.09297 \ Btu/lbm$

Change in internal energy  

$\Delta u= u_2-u_1$

   = 38.09297-40.5485

  = -2.4556        

5 0
2 years ago
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