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zlopas [31]
4 years ago
10

How many joules are needed to heat 8.50 grams of ice from-10.0

Chemistry
1 answer:
Stolb23 [73]4 years ago
4 0

Answer:

0.1

Explanation:

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How many neutrons does an element have whose electronic formula is 1s²2s²2p⁵​
Flura [38]

Answer:

it have 10 neutrons and it is Fluorine(F).

4 0
3 years ago
Example of a neutral mutation?
Norma-Jean [14]

The answer is D

Explanation: A RED FLOWER WITH ONE PART COLORED YELLOW

3 0
3 years ago
Read 2 more answers
g A 0.4395 g sample of aluminum reacts according to our experiment to produce alum. 5.1629 g of dried alum crystals are recovere
Alex

Answer:

92.75%

Explanation:

The overall chemical equation for the reaction in the preparation of alum from the aluminium can be expressed as:

\mathtt{2Al + 2KOH + 4H_2SO_4 +2H_2O   \to 2KAl(SO_4)_2 2H_2O +3H_2}

From above; we will see that 2 moles of Aluminium react with sulphuric acid and water to produce 2 moles o aluminium alum.

Therefore, the theoretical yield can be determined as:

=0.4395 \ g Al \times \dfrac{1 \ mol \ Al}{27 \ g Al }\times \dfrac{2 \ mol \ KAl(SO_4)_2}{2 \  mol \ Al}\times \dfrac{294.23 \ KAl(SO_4)_2}{1 \ mol \ KAl(SO_4)_2}

= 4.789g of KAl(SO_4)_2

To find the percent yield, we need to divide the actual yield by the theoretical yield and then multiply it with 100.

∴

percent yield = ( mass of alum(g)/theoretical yield(g) ) × 100

percent yield = ( 4.789g / 5.1629g ) × 100%

percent yield = 0.9275 × 100%

percent yield = 92.75%

Thus, the percent yield of the experiment 92.75%

8 0
3 years ago
How many valence electrons does boron need to be stable?
MAVERICK [17]
Because Boron has 3 valence electrons it will need to lose valence electrons to have a (in this case) a empty valence shell. This means that it will lose 3 valence electrons to become stable
8 0
4 years ago
Calculate the [OH-] and the pH for a solution of 0.24M methylamine, CH3NH2. Kb = 3.7 X 10-4.
Naddika [18.5K]

Answer:

[OH^-]=9.24x10^{-3}M.

pH=11.97.

Explanation:

Hello,

In this case, since the ionization of methylamine is:

CH_3NH_2(aq)+H_2O(l)\rightleftharpoons CH_3NH_3^+(aq)+OH^-(aq)

The equilibrium expression is:

Kb=\frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

And in terms of the reaction extent x which is equal to the concentration of  OH⁻ as well as that of CH₃NH₃⁺ via ice procedure we can write:

3.7x10^{-4}=\frac{x*x}{024-x}

Whose solution for x via quadratic equation is 9.24x10⁻³ M since the other solution is negative so it is avoided. Therefore, the concentration of OH⁻ is:

[OH^-]=x=9.24x10^{-3}M

With which we can compute the pOH at first:

pOH=-log([OH^-])=-log(9.24x10^{-3})=2.034

Then, since pH and pOH are related via:

pH+pOH=14

The pH turns out:

pH=14-pOH=14-2.034\\\\pH=11.97

Best regards.

8 0
3 years ago
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