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2 years ago

7

Nuclear energy comes from splitting atoms of __________ to generate heat.

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Answer:

Nuclear energy originates from the splitting of uranium atoms – a process called fission. This generates heat to produce steam, which is used by a turbine generator to generate electricity. Because nuclear power plants do not burn fuel, they do not produce greenhouse gas emissions.

Explanation:

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A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness

Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

$\sigma_h = \frac{Pd}{2t}$

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

$\sigma_l = \frac{Pd}{4t}$

The letters have the same meaning as before.

Then he hoop stress would be,

$\sigma_h = \frac{Pd}{2t}$

$\sigma_h = \frac{75 \times 8}{2\times 0.25}$

$\sigma_h = 1200psi$

And the longitudinal stress would be

$\sigma_l = \frac{Pd}{4t}$

$\sigma_l = \frac{75\times 8}{4\times 0.25}$

$\sigma_l = 600Psi$

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

$\tau_{max} = \frac{\sigma_h}{2}$

$\tau_{max} = \frac{1200}{2}$

$\tau_{max} = 600Psi$

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0

3 years ago

The force of gravity is (4 points) 1 a contact force 2 a distance force 3 an electrical force 4 a magnetic force

d1i1m1o1n [39]

It is a distance force

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3 years ago

What is the speed of a wave with a period of 25 sec/cycle and a wavelength of 15 m/cycle?please help me !

Nuetrik [128]

The answer of this question is 0.6m/s

5 0

3 years ago

How do the temperature curves in your graph show the range of temperature?

Alexeev081 [22]

Answer:

Step-by-step Explanation:

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3 years ago

You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 38.5∘ from the ground with an

zheka24 [161]

The ball's horizontal position in the air is

$x=\left(27.5\dfrac{\rm m}{\rm s}\right)\cos38.5^\circ t$

It hits the wall when $x=17.5\,\mathrm m$ , which happens at

$17.5\,\mathrm m=\left(27.5\dfrac{\rm m}{\rm s}\right)\cos38.5^\circ t\implies t\approx0.813\,\mathrm s$

Meanwhile, the ball's vertical position is

$y=\left(27.5\dfrac{\rm m}{\rm s}\right)\sin38.5^\circ t-\dfrac g2t^2$

where $g$ is the acceleration due to gravity, 9.80 m/s^2.

At the time the ball hits the wall, its vertical position (relative to its initial position) is

$y=\left(27.5\dfrac{\rm m}{\rm s}\right)\sin38.5^\circ(0.813\,\mathrm s)-\dfrac g2(0.813\,\mathrm s)^2\approx\boxed{10.7\,\mathrm m}$

5 0

3 years ago