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Lena [83]
3 years ago
15

How do the temperature curves in your graph show the range of temperature?

Physics
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

Step-by-step Explanation:

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When are Waves produced​
serg [7]

Answer:

Waves are caused by wind, or are created by the friction between wind and surface water

Explanation:

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3 years ago
A medieval instrument used to determine the position of the sun:
Stels [109]

Answer: astrolabe

Explanation:

4 0
2 years ago
Dan is gliding on his skateboard at 4.00m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at 6
frozen [14]

To solve this problem we will apply the concepts related to the conservation of the Momentum. For this purpose we will define the momentum as the product between mass and velocity, and by conservation the initial momentum will be equal to the final momentum. Mathematically this is,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m_{1,2} = Mass of Dan and Skateboard respectively

u_{1,2} = Initial velocity of Dan and Skateboard respectively

v_{1,2} = Final velocity of Dan and Skateboard respectively

Our values are:

Dan's mass

m_1 = 60kg

Mass of the skateboard

m_2 = 7.0kg

Both have the same initial velocity, then

u_1= u_2 = 4m/s

Final velocity of Skateboard is

v_2 = 6m/s

Rearranging to find the final velocity of Dan we have then,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

m_1v_1+m_2v_2 = (m_1+m_2)u_1

v_1 = \frac{ (m_1+m_2)u_1 -m_2v_2}{m_1}

Replacing,

v_1 = \frac{(60+7)(4)-(7)(6)}{60}

v_1 = 3.76m/s

Therefore Dan will touch the ground at a speed of 3.76m/s

5 0
4 years ago
A merry go round has rotational inertia (moment of inertia) of 73.0 kg/m^2 and is rotating at a constant speed of 30.0 rads./sec
valentinak56 [21]
The angular speed is 64 mph
4 0
2 years ago
Your outlets at home are rated at 120 V, i.e. the two prongs have on average a potential difference of 120V. If you transfer 2.7
hodyreva [135]

Answer:

E =230.4 MJ

Explanation:

As 1 mole of electron =  6X 10^23 particles.

charge of an electron is 1.6 X 10 ^-19 C

Finding Charge:

(6X10^23 ) (2.7)(1.6X10^-19 C)

i.e. 192 K C

now  to find the energy released from electrons

V=E/q

E=V X q

i.e E = 120 V X 192 K C

E =230.4 MJ

4 0
3 years ago
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