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Tomtit [17]
3 years ago
9

Given that kb for c6h5nh2 is 1.7 × 10-9 at 25 °c, what is the value of ka for c6h5nh3 at 25 °c?

Chemistry
1 answer:
lina2011 [118]3 years ago
7 0

Answer: k_a for C_6H_5NH_3^+ at 25°C is 0.588\times 10^{-4}

Explanation: We are given k_b of C_6H_5NH_2 at 25°C which is 1.7\times 10^{-9}

To calculate the k_a of C_6H_5NH_3^+, we use the formula:

k_w=k_a\times k_b

k_w\text{ at }25^o=1\times 10^{-14}

Putting values in above equation, we get:

1\times 10^{-14}=k_a\times (1.7\times 10^{-9})\\k_a=0.588\times 10^{-5}

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What is indicated by the methyl-prefix?
lozanna [386]

Answer:

B.) The molecule is a branched hydrocarbon.

Explanation:

A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.

6 0
1 year ago
Explain how to convert a mass of compound A to a mass of compound D in words with no equations using the following reaction 2A +
leonid [27]

Answer:

Explanation:

The given reaction equation is:

                2A + 4B → C + 3D

We know the mass of compound A in the reaction above. We are to find the mass of compound D.

We simply work from the known mass to calculate the mass of the unkown compound D

Using the mole concept, we can find the unknown mass.

Procedures

  • We first find the molar mass of the compound A from the atomic units of the constituent elements.
  • We then use the molar mass of A to calculate its number of moles using the expression below:  

            Number of moles of A = \frac{mass of A}{molar mass of A}

  • Using the known number of moles of A, we can work out the number of moles of D.

           From the balanced equation of the reaction, it is shown that:

         2 moles of compound A was used up to produced 3 moles of D

  Then \frac{3}{2} x number of moles of A would give the number of moles of D

  • Now that we know the number of moles of D, we can find its mass using the expression below:

             Mass of D = number of moles of D x molar mass of D

8 0
2 years ago
Consider the following reaction at 25 °C: 4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s) An equilibrium mixture contains 1.0 mol Fe, 1.0 × 10–3 mol
tino4ka555 [31]

Answer:

Kc = Kc = 8.0 * 10^9

Kp = 5.5 *10^5

Explanation:

Step 1: Data given

Temperature = 25.0 °C

Number of moles Fe = 1.0 moles

Number of moles O2 = 1.0 * 10^-3 moles

Number of moles Fe2O3 = 2.0 moles

Volume = 2.0 L

Step 2: The balanced equation

4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)

Step 3: Calculate molarity

Molarity = moles / volume

[Fe] = 1.0 moles / 2.0 L

[Fe] = 0.5 M

[O2] = 0.001 moles / 2.0 L

[O2] = 0.0005 M

[Fe2O3] = 2.0 moles / 2.0 L

[Fe2O3] = 1.0 M

Step 4: Calculate Kc

Kc =1/ [O2]³

Kc = 1/0,.000000000125

Kc = 8.0 * 10^9

Step 5: Calculate Kp

Kp = Kc*(R*T)^Δn

⇒with Kc = 8.0*10^9

⇒with R = 0.08206 L*atm /mol*K

⇒with T = 298 K

⇒with Δn = -3

Kp = 8.10^9 *(0.08206 * 298)^-3

Kp = 5.5 *10^5

4 0
2 years ago
What coefficients should be added in order to make this a balanced equation?
Vanyuwa [196]

Answer:

Hello

Coefficients are 1,3,2,1

Explanation

6 0
3 years ago
Two ice skaters push off against one another starting from a stationary position. The 45.0-kg skater acquires a speed of 0.375 m
zalisa [80]

Answer:

The speed of the 60.0 kg skater should be 0.281 m/s

Explanation:

<u>Step 1: </u>Data given

Mass of skater 1 = 45.0 kg

speed of skater 1 = 0.375 m/s

Mass of skater 2 = 60.0 kg

<u>Step 2:</u> Calculate the speed of skater 2

To solve this problem, we will use 'Conservation of momenton'. This means  the momentum before the push equals the momentum after.

momentum p = m*v

Momentum p(before) = momentum p(after)

m1*v1 = m2 * v2

⇒ with m1 = mass of skater 1 = 45.0 kg

⇒ with v1 = the velocity of skater 1 = 0.375 m/s

⇒ with m2 = the mass of skater 2 = 60.0 kg

⇒ with v2 = the velocity of skater 2 = TO BE DETERMINED

45.0 * 0.375 = 60.0 * v2

v2 = (45.0*0.375)/60

v2 = 0.281 m/s

The speed of the 60.0 kg skater should be 0.281 m/s

6 0
3 years ago
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