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Assume Specific Heat capacity of water = 4.186 J/g<span>°C
100g sample,
Q=mc</span>Δθ<span>
8360=100(4.186)(Final Temp.-22.0)
Final Temperature </span>≈<span>41.97</span><span>°C</span>
Answer: Beryllium phosphide
Explanation:it has a molecular weigt of 88.98407 g/mol
its CID is 16453515
Answer:
Question Answer
The half-life of cobalt-60 is 5.26 years. How many half-lives have passed in 10.52 years? 2
12.5% of a radioactive sample are left. How many half-lives have passed? 3
After 3 half-lives, how much of a 400 gram sample of radioactive uranium remains? 50g
Explanation:
Answer:
See explanation
Explanation:
A word equation tries to depict a chemical reaction in words. Letters rather than only chemical formulas are used to show the reaction equation.
Now we want to write a word equation that shows the reaction of sodium hydroxide solution and aluminium sulphate solution:
Alumunium sulphate + sodium hydroxide ------>Aluminium hydroxide + sodium sulphate
