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SashulF [63]
4 years ago
8

How do I solve for angles 1-5?

Physics
1 answer:
pychu [463]4 years ago
3 0

Keep in mind that the angles of a triangle add up to 180°. The total angle measurement of a line segment is also 180°. The total angle measurement of a right angle is 90°.

Look at the bottom side of the rectangle. It intersects with two lines to form 3 angles: a 70° angle and two angles θ₁

Take the sum of the three angles and set the sum equal to 180°, then solve for θ₁:

2θ₁ + 70° = 180°

2θ₁ = 110°

θ₁ = 55°

We have two right triangles inscribed in the rectangle. Let's focus on the triangle on the right side. It consists of the angles θ₁, θ₃, and a right angle. Take the sum of the three angles and set the sum equal to 180° then solve for θ₃:

θ₁ + θ₃ + 90° = 180°

55° + θ₃ + 90° = 180°

θ₃ = 35°

The triangle on the left side is just the mirror image of the triangle on the right side. These triangles have the same angle measurements, so we can say right away that θ₄ = 35°

Angles θ₂ & θ₃ and θ₄ & θ₅ make up right angles, which have a total angle measurement of 90°. θ₃ = θ₄ = 35°, therefore we can say that θ₂ = θ₅ = 90° - 35°

θ₂ = θ₅ = 55°

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Provide the following information for each of the three types of radiations from naturally radioactive materials. Be sure to inc
scoundrel [369]

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5 0
3 years ago
If riding a lawnmower engine exerts 19 hp in one minute to move the lawnmower how much work is done
ioda

Answer:

the work done by the lawnmower is 236.14 J.

Explanation:

Given;

power exerted by the lawnmower engine, P = 19 hp

time in which the power was exerted, t = 1 minute = 60 s.

1 hp = 745.7 watts

The work done by the lawnmower is calculated as follows;

Work = Energy = \frac{Power}{time} \\\\Work = \frac{(19 \times 745.7)}{60} = 236.14 \ J

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3 years ago
A(n) 96.1 g ball is dropped from a height of 59.1 cm above a spring of negligible mass.The ball compresses the spring to a maxim
Serhud [2]

Answer:

Explanation:

Mass of ball Is m=96.1g=0.0961kg

Height above spring is 59.1cm

L=0.591m

Extension of the spring is 4.75403cm

e=0.0475403m

Then the distance the ball traveled is H=L+e

H=0.591+0.0475403

H=0.6385403m

Then, the potential energy of the ball is given as

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P.E=0.0961×9.81×0.6385403

P.E=0.602J

From conservation of energy, energy cannot be created nor destroy but can be transferred from one form to another

Then, the P.E is transferred to the work done by the spring

Then, Work done by spring is given as

W=½ke²

W=P.E=½×k×0.0475403²

0.602=½×k×0.0475403²

k=0.602×2/0.0475403²

k=532.72N/m

The spring constant is 532.72 N/m

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