Consider a point 0.5 m above the midpoint of the two charges. As you can verify by removing one of the positive charges, the ele
ctric field due to only one of the positive charges is about 18 V/m. What is the magnitude of the total electric field due to both charges at this location
the magnitude of the total electric field is 25 V/m
Explanation:
Given data
point above = 0.5 m
charges = 18 V/m
to find out
the magnitude of the total electric field
solution
the magnitude of the total electric field is 25 V/m because number is less than the twice magnitude of field by every charge and the horizontal component in electric field by every charge cancel out and vertical component in field added together