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Lady bird [3.3K]
3 years ago
9

The primary of a step-up transformer is connected across the terminals of a standard wall socket, and resistor 1 with a resistan

ce r1 is connected across the secondary. the current in the resistor is then measured. next, resistor 2 with a resistance r2 is connected directly across the terminals of the wall socket (without the transformer). the current in this resistor is also measured and found to be the same as the current in resistor 1. how does the resistance r2 compare to the resistance r1? answers
Physics
1 answer:
alexira [117]3 years ago
3 0
The turns ratio is the factor that determines voltage andcurrent. In order to have the same current across the resistorin the primary as the resistor in the secondary, then:--N(p) = Primary turnsN(s) = Secondary turnsR(2) = Primary resistorR(1) = Secondary resistor--R(2)/R(1) = N(p)/N(s)R(2) = R(1)*(N(p)/N(s))--If arbitrary values are plugged in, you will see that this step up transformer will require 2x the resistance required in the secondary, R(1), to obtain the same current. Thus R(2) will be 1/2 the value of R(1). This is due to the stepped up voltage in the secondary.
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How much extra water does a 147-lb concrete canoe displace compared to an ultralightweight 38-lb kevlar canoe of the same size c
romanna [79]

We use the formula, to calculate the volume of water displaced by concrete canoe,

V =\frac{W}{\gamma }

Here, W is the weight of concrete canoe and \gamma is the specific weight of water and its value is 62.4\ lb/ft^3.

So,

V =\frac{ 147\ lb}{62.4\ lb/ft^3}=2.356\ ft^3.

Now the volume of water occupied in ultra lightweight kevlar canoe,

v=\frac{w}{\gamma}

Here, w is weight of  kevlar canoe.

So,

v=\frac{38\ lb}{62.4\ lb/ft^3} =0.6089\ ft^3

Thus, the volume of water displaced,

=V-v=2.356\ ft^3-0.6089\ ft^3=2.19\ ft^3.

Hence, the volume of water displaced canoe compared to an ultra-lightweight  kevlar canoe is 2.19\ ft^3

5 0
3 years ago
When two oceanic plates collide, it creates _____.
jonny [76]

At the subduction zone a very deep trench is formed in the ocean floor. Oceanic and oceanic plate convergence result in the formation of volcano chains. The crust that is pulled under or subducted melts to form magma. This magma rises to the top of the overriding oceanic plates and erupts on the ocean floor.
So the answer would be Volcano
5 0
4 years ago
Read 2 more answers
a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
3 years ago
A wheel with moment of inertia 25 kg. m2 and angular velocity 10 rad/s begins to speed up, with angular acceleration 15 rad/sec2
Pani-rosa [81]

Answer:

(A) Angular speed 40 rad/sec

Rotation = 50 rad

(b) 37812.5 J

Explanation:

We have given moment of inertia of the wheel I=25kgm^2

Initial angular velocity of the wheel \omega _0=10rad/sec

Angular acceleration \alpha =15rad/sec^2

(a) We know that \omega =\omega _0+\alpha t

We have given t = 2 sec

So \omega =10+15\times  2=40rad/sec

Now \Theta =\omega _0t+\frac{1}{2}\alpha t^2=10\times 2+\frac{1}{2}\times 15\times 2^2=50rad

(b) After 3 sec \omega =10+15\times 3=55rad/sec

We know that kinetic energy is given by Ke=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 25\times 55^2=37812.5J

7 0
3 years ago
If a 6V battery is connected to a light bulb whose resistance is 55,000Ω How much current will flow in the circuit?
notka56 [123]

Answer:

Current, I = 0.000109 Amps

Explanation:

Given the following data;

Voltage = 6V

Resistance = 55,000 Ohms

To find the current flowing through the circuit;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

V = IR

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Making current the subject of formula, we have;

I = \frac {V}{R}

Substituting into the formula, we have;

I = \frac {6}{55000}

Current, I = 0.000109 Amps

5 0
3 years ago
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