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Kay [80]
3 years ago
15

A 0.50 m3 drum was filled with 0.49 m3 of liquid water at 25oC and the remaining volume was water vapor without any air. The dru

m was then sealed and heated to 140oC. What happened to this system
Engineering
1 answer:
timurjin [86]3 years ago
5 0

Answer:

There is not going to be pressure build up in the  system,that is isobaric process.

Explanation:

Assumptions to be made

1.  No mass is gained or lost during the heating process.

2. There are no friction losses,so work is transmitted efficiently.

3. It was started the water in the drum and its surrounding have same temperature.

4. This system is closed,so there is no mass transfer across its boundaries.

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What type of siege engines were used by Saladin to capture Jerusalem in 1187?
mariarad [96]

Answer:

LOTS

Explanation:

Catapults, Towers, and Trebuchets were all used by Saladin to capture Jerusalem in 1187

8 0
2 years ago
When the electrical connection to the alternator from the battery is not tight, it can cause?
Oksi-84 [34.3K]

Answer:

affects the flow of electricity

Explanation:

A loose battery terminal affects the flow of electricity. There is less power going to the electrical systems and the vehicle will not start or start sluggishly. Also, a loose battery terminal causes the car's electrical components like navigation, car lights, and audio among others to dim or fail completely.

3 0
2 years ago
Water exerts little pressure on a building so it has no implications on foundation design.
777dan777 [17]

Fact

Explanation:

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7 0
2 years ago
Part of a control linkage for an airplane consists of a rigid member CB and a flexible cable AB Originally the cable is unstretc
AnnZ [28]

Answer:

e_{ab} =  4.18*10^(-3)

Explanation:

This question will be solved with the help of diagram (see attachment)

Given:

Δ∅ = 0.50 degrees (correction)

BC = 800 mm

AC = 600 mm

Solution:

We use coordinate system with point C as origin (0,0)

Hence,

Point A = (600,0)

Point B = (0,800)

The change in length or displacement can be calculated BB' :

BB' = BC * tan (Δ∅) = (800 mm) * tan (0.5) = 6.9815 mm

Hence, Point B' = (-6.9815,800) and we calculate distance A and B

AB = \sqrt{600^2 + 800^2} = 1000 mm

We calculate distance A and B'

AB' = \sqrt{(600 - (-6.9815))^2 + (0-800)^2} = 1004.2 mm

Normal Strain in AB is:

e_{ab} = \frac{AB' - AB}{AB} \\\\= \frac{1004.2 - 1000}{100}\\\\= 4.18 * 10^(-3)

The solution is :

e_{ab} =  4.18 * 10^(-3)

6 0
2 years ago
We are used to connect the external devices and power supply to a computer. My anagram is torps
lutik1710 [3]

Answer: Ports  

Explanation:

Ports are the devices tat is used for connection of input devices and output devices wit computer.Te links created by ports between peripheral and computing system connects devices such as monitors, keyboard,modems , printer speaker s etc.  

External devices get plugged into ports which are embedded on motherboard of the computing system to establish peripheral connection.

4 0
3 years ago
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