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Katen [24]
3 years ago
9

In severe head-on automobile accidents, a deceleration of 60 g’s or more (1 g 5 32.2 ft/s2) often results in a fatality. What fo

rce, in lbf, acts on a child whose mass is 50 lb, when subjected to a deceleration of 60 g’s?
Physics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

The resulting force on the child is 3000 lbf

Explanation:

To find the force that acts on a child of 50 lb with a deceleration of 60 g's, we can use the formula:

Force = mass * acceleration

To find the force in lbf, we need to use the mass in lb and the acceleration in g (standard unit of gravity).

So we have that:

Force = 50 * 60

Force = 3000 lbf

So the resulting force on the child is 3000 lbf.

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The area of a rectangular park is 4 mi^2. The park has a width that is equal to "w", and a length that is 3 mi longer than the w
goldfiish [28.3K]

Answer:

l= 4 mi   : width of the park

w= 1 mi  : length of the park

Explanation:

Formula to find the area of ​​the rectangle:

A= w*l       Formula(1)

Where,

A is the area of the  rectangle in mi²

w is the  width of the rectangle in mi

l is the  width of the rectangle in mi

Known data

A =  4 mi²

l = (w+3)mi    Equation (1)

Problem development

We replace the data in the formula (1)

A= w*l  

4 = w* (w+3)

4= w²+3w

w²+3w-4= 0

We factor the equation:

We look for two numbers whose sum is 3 and whose multiplication is -4

(w-1)(w+4) = 0 Equation (2)

The values ​​of w for which the equation (2) is zero are:

w = 1 and w = -4

We take the positive value w = 1 because w is a dimension and cannot be negative.

w  = 1 mi  :width of the park

We replace w  = 1 mi  in the equation (1) to calculate the length of the park:

l=  (w+3) mi

l= ( 1+3) mi

l= 4 mi

8 0
3 years ago
By using electroscope, if the body is negatively charged then due to electrostatic induction, then on the leaves there will be a
Kryger [21]

(b) negative charge

This is the answer

6 0
3 years ago
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PLEASE HELP ME WITH THIS ONE QUESTION
sdas [7]

Answer:

0.34 m

Explanation:

From the question,

v = λf................ Equation 1

Where v = speed of sound, f = frequency, λ = Wave length

Make λ the subject of the equation

λ = v/f............... Equation 2

Given: v = 340 m/s, f = 500 Hz.

Substitute these values into equation 2

λ = 340/500

λ = 0.68 m

But,  the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length

Therefore,

λ/2 = 0.68/2

λ/2 = 0.34 m

Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m

6 0
3 years ago
What is rotation in your own words. and you have to be detailed
attashe74 [19]

Answer:

The action of rotating around something like for ex.. Child A stands in the middle of a room while Child B goes around Child A, Child B is rotating around Child A. Another ex. is; The earth rotates around the sun every 365 days the earth is rotating or going around the sun in a circle. So rotating to me is the act of rotating around something in any way shape or form.

PS: A middle schooler answered this so if you don't wanna believe me or think I'm wrong because I am younger you do you.

7 0
3 years ago
An object on earth weighs 120 N. What is it’s mass ?
inna [77]
Weight = (mass) x (gravity)

120 N = (mass) x (9.8 m/s²)

Mass = (120 N) / (9.8 m/s²)

Mass = 12.24 kg  (B)
7 0
3 years ago
Read 2 more answers
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