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3 years ago

True or False: Electrons in each lower level are filled before electrons fill

Chemistry

1 answer:

ale4655 [162]3 years ago

5 0

the answer is 1....true

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How many hydrogen atoms are in 105 g of water?

mel-nik [20]

Moles of water atoms = mass/molecular weight = 105/18 = 5.83 mol. Number of moles of hydrogen in water = 2 x moles of water = 11.66. Number of H atoms in water = moles of hydrogen x 6.02 x 10^23 = 7.019 x 10^24 ~ 7.02 x 10^24 atoms. Hope this helps.

3 0

3 years ago

Fluorine + sodium chloride → sodium fluoride + __________. What is the missing chemical name?

Deffense [45]

Answer:

Chlorine (Cl)

Explanation:

The equation would be:

$F+NaCl$ → $NaF + Cl$

This is because no atom is lost in a reaction. Chlorine would be the missing chemical as it is on the other side of the equation and needs to be accounted for on the products side.

7 0

2 years ago

An acid

tekilochka [14]

The answer is A. Has a low pH in solution.

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3 years ago

The concentration of urea in a solution prepared by dissolving 16 g of urea in 20 g of H2OH2O is ________% by mass. The molar ma

Arada [10]

Answer:

Explanation:

Given that :

Mass of solute = Mass of urea = 16g

Mass of water = 20g

Mass of solution = (mass of solute + mass of solvent) = (mass of urea + mass of water) = (16g + 20g) = 36g

Percentage Mass = (mass of solute / mass of solution) * 100%

Percentage Mass = (16 / 36) * 100%

Percentage Mass = 0.4444444 x 100%

Percentage Mass = 44.44%

Percentage Mass = 44%

4 0

2 years ago

3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and t

DanielleElmas [232]

Answer:

4.67 kg

Explanation:

Given data

Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm

Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

$V = 75.0 cm \times 55.0 cm \times 0.10 cm = 413 cm^{3}$

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

$\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} } \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg$

6 0

2 years ago