The answer is a. True. This is also known as the Le Chatelier's principle or The Equilibrium Law which states that if a chemical reaction is at equilibrium and then experiences changes in the condition of the reaction such as changes in concentration, pressure, or temperature of products or reactants, the system will naturally shift to achieve a new equilibrium state.
Answer:
Explanation:
We can use the Arrhenius equation to relate the activation energy and the rate constant, k, of a given reaction:
k=Ae−Ea/RT
In this equation, R is the ideal gas constant, which has a value 8.314 J/mol/K, T is temperature on the Kelvin scale, Ea is the activation energy in joules per mole, e is the constant 2.7183, and A is a constant called the frequency factor, which is related to the frequency of collisions and the orientation of the reacting molecules.
Both postulates of the collision theory of reaction rates are accommodated in the Arrhenius equation. The frequency factor A is related to the rate at which collisions having the correct orientation occur. The exponential term,
e−Ea/RT, is related to the fraction of collisions providing adequate energy to overcome the activation barrier of the reaction.
The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs
<h3>what do you mean by half-life?</h3>
A substance's half-life is the amount of time it takes for half of it to decompose.
<h3>What is a half-life example?</h3>
Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.
When n half-lives have passed, the formula for estimating the amount still left is:-
A=A°/2^n
where,
A=initial amount
A°=remaining amount
n=t/t_{1/2}
A=150/2^t/30yrs
Learn more about half-life here:-
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