Answer:
Explanation:
C decays by a process called beta decay. During this process, an atom of 14C decays into an atom of 14N, during which one of the neutrons in the carbon atom becomes a proton. This increases the number of protons in the atom by one, creating a nitrogen atom rather than a carbon atom.
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

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Answer:
no, the correct answer is NaCI
Explanation:
you're welcome
a) NH₃ molecules have stronger intermolecular attractions than CH₄ molecules.
Explanation:
Ammonia molecules have stronger intermolecular attractions compared to methane.
Ammonia molecules have london dispersion forces and hydrogen bonds between their molecules.
Methane molecules have only london dispersion forces in their structure.
- hydrogen bonds are very strong attractive forces between molecules in which the hydrogen of a molecule is attracted by a more electronegative atom of another usually oxygen, nitrogen and fluorine.
- London dispersion forces are weak forces of attraction between heteronuclear atoms.
Learn more:
Hydrogen bonds brainly.com/question/10602513
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
mol/dm³ is measure for molarity