How do you cram for a sicence test
2 answers:
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Explanation:
Draw a free body diagram for each disc.
Disc A has three forces acting on it: 86.5 N up, T₁ down, and Wa down.
∑F = ma
86.5 N − T₁ − Wa = 0
Wa = 86.5 N − T₁
ma × 9.8 m/s² = 86.5 N − 55.6 N
ma = 3.2 kg
Disc B has three forces acting on it: T₁ up, T₂ down, and Wb down.
∑F = ma
T₁ − T₂ − Wb = 0
Wb = T₁ − T₂
mb × 9.8 m/s² = 55.6 N − 36.5 N
mb = 1.9 kg
Disc C has three forces acting on it: T₂ up, T₃ down, and Wc down.
∑F = ma
T₂ − T₃ − Wc = 0
Wc = T₂ − T₃
mc × 9.8 m/s² = 36.5 N − 9.6 N
mc = 2.7 kg
Disc D has two forces acting on it: T₃ up and Wd down.
∑F = ma
T₃ − Wd = 0
Wd = T₃
md × 9.8 m/s² = 9.6 N
md = 0.98 kg
Answer:
333.3 m
Explanation:
Given
Potential energy =......Equation(1)
We know that
Potential energy=mgh
Kinetic energy =
Now From the Equation(1)
The vertical component of force exerted by the hi.nge on the beam will be,142.10N.
To find the answer, we need to know more about the tension.
<h3>How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>- Let's draw the free body diagram of the system.
- To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.
- To find the answer, we have to find the tension,
- Thus, the vertical component of the force exerted by the hi.nge on the beam will be,
Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.
Learn more about the tension here:
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