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Olegator [25]
3 years ago
11

Helicopter blades withstand tremendous stresses. In addition to supporting the weight of a helicopter, they are spun at rapid ra

tes and experience large centripetal accelerations, especially at the tip. (a) Calculate the magnitude (in m/s2) of the centripetal acceleration at the tip of a 3.10 m long helicopter blade that rotates at 280 rev/min. m/s2 (b) Compare the linear speed of the tip with the speed of sound (taken to be 340 m/s). vtip vsound =
Physics
1 answer:
BabaBlast [244]3 years ago
4 0

Explanation:

It is given that,

Length of the helicopter, l = 3.1 m

The helicopter rotates, the length of helicopter will become the radius of circular path, r = 3.1 m

Angular speed of the helicopter, \omega=280\ rev/min=29.32\ rad/s

(a) The centripetal acceleration in terms of angular velocity is given by :

a_c=r\times \omega^2

a_c=3.1\times (29.32)^2

a_c=2664.95\ m/s^2

(b) Let v is the linear speed of the tip. The relation between the linear and angular speed is given by :

v=r\times \omega

v=3.1\times 29.32

v = 90.89 m/s

\dfrac{v_{tip}}{v_{sound}}=\dfrac{90.89}{340}=0.267

Hence, this is the required solution.

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