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kirill115 [55]
3 years ago
11

What is the mass of nickel(II) nitrate (182.71 g/mol) dissolved in 25.0 mL of 0.100 M Ni(NO3)2 solution? A) 157 g B) 0.250 g C)

4578 D) 0.4578 E) 4.00 g
Chemistry
1 answer:
marusya05 [52]3 years ago
5 0

Answer: 0.4578 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{182.71g/mol}  

V_s = volume of solution  in ml = 25.0 ml

0.100M=\frac{x\times 1000}{182.71\times 25}

x=0.4578g

Thus 0.4578 g of nickel(II) nitrate is to be dissolved in 25.0 mL of 0.100 M Ni(NO_3)_2 solution.

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