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3 years ago

14

Waves A and B have the same speed, but wave A has a shorter wavelength. Which wave has the higher frequency?

1 answer:

Nuetrik [128]3 years ago

3 0

Frequency and wavelength are inversely proportional.
A shorter wavelength implies a higher frequency.

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Reaction _______ refers to the tendency of a reaction to occur without the application of outside force or energy to sustain the

babymother [125]

<span>spontaneity is the answer, hope this helps!!</span>

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4 years ago

The measure of how quickly an object’s velocity changes is called

blsea [12.9K]

Acceleration I’m pretty sure

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4 years ago

Read 2 more answers

In outer space, a piece of rock continues moving at the same velocity for

Ray Of Light [21]

The absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

<h3>Absence of external force on the outer space</h3>

The outer space is almost an absolute vacuum, because it's nearly empty. There is no matter such as air in the outer space that will provide an external force needed to change the velocity of the piece of rock.

From Newton's first law of motion, an object in a state of rest or uniform motion in a straight line, will continue in that state unless it is acted upon by an external force.

Thus, the absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

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2 years ago

12. Suppose a person uses a mechanical iack to lift half the weight of a car with a

Likurg_2 [28]

a) The force that must be applied is 73.5 N

b) The actual efficiency is 82 %

Explanation:

a)

Since the jack is 100% efficient, all the input work is converted into output work. So we can write:

$W_{in} = W_{out}\\F_{in} d_{in} = F_{out} d_{out}$

where:

$F_{in}$ is the input force applied on the jack

$d_{in}$ is the arm of the input force

$F_{out}$ is the output force applied on the jack

$d_{out}$ is the arm of the output force

Here we have:

$F_{out}=\frac{mg}{2}= \frac{(1200 kg)(9.8 m/s^2)}{2}=5880 N$ is the output force (half the weight of the car)

$d_{in} = 40.0 cm = 0.40 m$ is the arm of the input force

$d_{out} = 5.0 mm = 0.005 m$ is the arm of the output force

Solving for $F_{in}$ , we find the force that must be applied in input to lift the car:

$F_{in} = \frac{F_{out}d_{out}}{d_{in}}=\frac{(5880)(0.005)}{0.40}=73.5 N$

b)

The efficiency of the jack is given by the ratio between the output work and the input work:

$\eta = \frac{W_{out}}{W_{in}}=\frac{F_{out}d_{out}}{F_{in}d_{in}}$

where we have:

$F_{out}=5880 N$ is the output force (half the weight of the car)

$d_{in} = 40.0 cm = 0.40 m$ is the arm of the input force

$d_{out} = 5.0 mm = 0.005 m$ is the arm of the output force

Here we are told that the input force this time is

$F_{in}=90.0N$

Substituting into the equation, we find the new efficiency of the jack:

$\eta = \frac{(5880)(0.005)}{(90.0)(0.40)}=0.82$

Which means an efficiency of 82%.

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#LearnwithBrainly

8 0

4 years ago

A particular uniform solid disk has a mass of 24.0 kg and a radius of 1.50 m. The disk is rotating about an axle passing through

Thepotemich [5.8K]

Answer:

$L = 81 Kg.m^2/s^2$

Explanation:

Angular momentum is calculated as:

L = I * ω

The inertia of the disc is:

$I = 1/2 * M *R^2 = 1/2 * 24 * (1.5)^2=27Kg.m^2$

So, the angular momentum is:

$L = 27 Kg.m^2* 3rad/s=81Kg.m^2/s^2$

6 0

4 years ago