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a_sh-v [17]
3 years ago
10

HELPPPPPPPPPP/AYUDAAAAAAAA

Chemistry
1 answer:
Anna [14]3 years ago
3 0

Answer:

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Explanation:

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Lridium-192 is an isotope of iridium and has a half-life of 73.83 days. if a laboratory experiment begins with 100 grams of irid
fiasKO [112]
Radioactive material undergoes first order dissociation kinetics.

For 1st order system,
k = 0.693 / t1/2
where, t 1/2 = half-life of the radioactive disintegration process.

Given that, t 1/2  = <span>73.83 days
Therefore, k = 0.009386 day-1

Also, for 1st order reaction,
k = </span>\frac{2.303}{t} log \frac{Co}{Ct}

Given that, Co = initial concentration of <span>Iridium-192 = 100 g

Therefore, </span>0.009386 = \frac{2.303}{t} log \frac{100}{Ct}

On rearranging we get, Ct = 100 (0.990656)^{t}

Answer: Ct = 100 (0.990656)^{t} equation approximates the amount of Iridium-192 present after t days
8 0
3 years ago
How many molecules of nitrogen gas are in 15 L of nitrogen gas
uranmaximum [27]

Answer:

3.98\times 10^{23}

Explanation:

Since we have $N_A$ number of molecules in 22.4 L, in 15 L we have:

$\frac{15}{22.4}\times 6.023 \times 10^{23}$ molecules.

5 0
3 years ago
Which two conditions can limit the usefulness of the kinetic-molecular theory in describing gas behavior?
adell [148]
-ideal gas: a hypothetical gas whose molecules exhibit no interaction and undergo elastic collision with each other and the walls of the container
-macroscopic properties: properties that can be visualized or measured by the naked eye; examples include pressure, temperature, and volume
6 0
3 years ago
Read 2 more answers
A food is initially at a moisture content of 90% dry basis. Calculate the moisture content in wet basis
Anvisha [2.4K]

Answer:

Moisture content in wet basis = 47.4 %    

Explanation:

<u>Moisture content expresses the amount of water present in a moist sample.</u> <u>Dry basis and wet basis are widely used to express moisture content.   </u>

The next equation express the moisture content in wet basis:  

                MC_{wb}=\frac{MC_{db}}{1+MC_{db}}

<em>where,  MC_{wb}: moisture content in wet basis and  </em>

<em>              MC_{db}: moisture content in dry basis    </em>

We now calculate the moisture content in wet basis:

MC_{wb}=\frac{MC_{db}}{1+MC_{db}}

MC_{wb}=\frac{0.90}{1+0.90}

MC_{wb}= 0.474 = 47.4 % wet basis    

Have a nice day!

8 0
4 years ago
How many grams are in 5.00 moles of sodium carbonate?
dimulka [17.4K]

Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

= 529.9422

grams

8 0
3 years ago
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