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Brut [27]
3 years ago
13

[4 points] Does the green LED emit light when you connect the banana plug wires across it? What does that say about the threshol

d voltage of the green LED compared to the blue LED?
Engineering
1 answer:
castortr0y [4]3 years ago
4 0

Yes, the green LED emits light when we connect the banana plug wires across it.

This indicates that the threshold voltage is lower for the green LED light than the blue.

<u>Explanation</u>:

A banana plug is named for its resemblance to the shape of a banana. They are wider in the middle of the plug, and narrower at the top and bottom. The banana plug can be easily plugged or unplugged into the ports of speaker or receiver.

LED lights emit photons when it is applied with electrical charge. LED lights are more efficient and last longer than incandescent light bulbs. Green light is commonly provides the calming effect. It is generally used in hyper-pigmentation treatment.

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A communication systems

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3 years ago
The viscosity of a fluid is 10 be measured by a viscometer constructed of two 75-cm-long concentric cylinders. The outer diamete
a_sh-v [17]

Answer:

0.023 Pa*s

Explanation:

The surface area of the side of the inner cylinder is:

A = π*d*l

A = π*0.15*0.75 = 0.35 m^2

At 200 rpm the inner cylinder has a tangential speed of:

u = w * r

u = w * d/2

w = 200 rpm * 2π / 60 = 20.9 rad/s

u = 20.9 * 0.15 / 2 = 1.57 m/s

The torque is of 0.8 N*m, this means that the force is:

T = F * r

F = T / r

F = 2*T / d

For Newtoninan fluids with two plates moving respect of each other with a  fluid between the viscous friction force would be:

F = μ*A*u / y

Where

μ: viscocity

y: separation between pates

A: surface area of the plates

Then:

2*T / d = μ*A*u/y

Rearranging:

μ = 2*T*y / (d*A*u)

μ = 2*0.8*0.0012 / (0.15*0.35*1.57) = 0.023 Pa*s

5 0
3 years ago
Wattage is:
Ksju [112]

Answer:

c.Both A and B.

Explanation:

the wattage is c and d

7 0
2 years ago
Which manufacturing process can create complex solid objects of metal such as the one shown in the image
Cerrena [4.2K]
Casting is the correct answer
8 0
2 years ago
Read 2 more answers
An oxygen–nitrogen mixture consists of 35 kg of oxygen and 40 kg of nitrogen. This mixture is cooled to 84 K at 0.1 MPa pressure
Tamiku [17]

Answer:

The mass of oxygen in liquid phase = 14.703 kg

The mass of oxygen in the vapor phase = 20.302 kg

Explanation:

Given that:

The mass of the oxygen m_{O_2} = 35 kg

The mass of the nitrogen m_{N_2} = 40 kg

The cooling temperature of the mixture T = 84 K

The cooling pressure of the mixture P = 0.1 MPa

From the equilibrium diagram for te-phase mixture od oxygen-nitrogen as 0.1 MPa graph. The properties of liquid and vapor percentages are obtained.

i.e.

Liquid percentage of O_2 = 70% = 0.70

Vapor percentage of O_2 = 34% = 0.34

The molar mass (mm) of oxygen and nitrogen are 32 g/mol and 28 g/mol respectively

Thus, the number of moles of each component is:

number of moles of oxygen = 35/32

number of moles of oxygen =  1.0938 kmol

number of moles of nitrogen = 40/28

number of moles of nitrogen = 1.4286  kmol

Hence, the total no. of moles in the mixture is:

N_{total} = 1.0938+1.4286

N_{total} = 2.5224 \ kmol

So, the total no of moles in the whole system is:

N_f + N_g = 2.5224 --- (1)

The total number of moles for oxygen in the system is

0.7 \ N_f + 0.34 \ N_g =  1.0938 --- (2)

From equation (1), let N_f = 2.5224 - N_g, then replace the value of N_f into equation (2)

∴

0.7(2.5224 - N_g) + 0.34 N_g = 1.0938

1.76568 - 0.7 N_g + 0.34 N_g = 1.0938

1.76568 - 0.36 N_g = 1.0938

1.76568 - 1.0938 = 0.36 N_g

0.67188  = 0.36 N_g

N_g = 0.67188/0.36

N_g = 1.866

From equation (1)

N_f + N_g = 2.5224

N_f + 1.866 = 2.5224

N_f = 2.5224 - 1.866

N_f = 0.6564

Thus, the mass of oxygen in the liquid and vapor phases is:

m_{fO_2} = 0.7 \times 0.6564 \times 32

m_{fO_2} = 14.703 \ kg

The mass of oxygen in liquid phase = 14.703 kg

m_{g_O_2} = 0.34 \times 1.866 \times 32

m_{g_O_2} = 20.302 \ kg

The mass of oxygen in the vapor phase = 20.302 kg

8 0
3 years ago
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