Answer Explanation : The general principles for design for assembly (DFA) are,
- MINIMIZE NUMBER OF COMPONENT
- USE STANDARD COMMERCIALLY AVAILABLE COMPONENTS
- USE COMMON PARTS ACROSS PRODUCT LINES
- DESIGN FOR EASE OF PART FABRICATION
- DESIGN PARTS WITH TOLERANCE THAT ARE WITHIN PROCESS CAPABILITY
- MINIMIZE USE OF FLEXIBLE COMPONENT
- DESIGN FOR EASE OF ASSEMBLY
- USE MODULAR DESIGN
- REDUCE ADJUSTMENT REQUIRED
STEPS TO MINIMIZE THE NUMBER OF PARTS
- USE OF INCORPORATE HINGS
- USE OF INTEGRAL SPRINGS
- USE OF SNAP FITS
- USE OF GUIDES BEARINGS
- USE OF COVERS
Answer:
During installation, the air transformer should be located at least 25 feet minimum from the compressor unit
Explanation:
An air transformer is used to remove the dirt, water and oil in the compressed air and to filter as well as to provide air regulation and are required in spray finishing tasks that calls for a regulated clean and dry supply of air
The air transformer measures the pressure of the regulated air and can also come with air outlets for air operated tools, blow guns, spray guns, as well as for other purposes
In order to operate efficiently, the air transformer are required to be installed at a minimum distance of 25 feet (7.6 m) from the compressor unit.
Answer:
Here, The CML is used for efficient portfolios whereas the SML applies to all portfolios or securities
Considering the seperation theorem, The separation theorem states that the investment decision is sepaarte from the financing decision.
This implies that The SML can be used to analyze the relationship between risk and requried return for all assets.
Under the separation theorem investors should Hold the same portfolio of risky assets and the same expected return but at different levels of risk
Explanation:
See answer
Explanation:
A.
H = Aeσ^4
Using the stefan Boltzmann law
When we differentiate
dH/dT = 4AeσT³
dH/dT = 4(0.15)(0.9)(5.67)(10^-8)(650)³
= 8.4085
Exact error = 8.4085x20
= 168.17
H(650) = 0.15(0.9)(5.67)(10^-8)(650)⁴
= 1366.376watts
B.
Verifying values
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(670)⁴
= 1542.468
H(T+ΔT) = 0.15(0.9)(5.67)(10^-8)(630)⁴
= 1205.8104
Error = 1542.468-1205.8104/2
= 168.329
ΔT = 40
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(690)⁴
= 1735.05
H(T-ΔT) = 0.15(0.9)(5.67)(10^-8)(610)⁴
= 1735.05-1059.83/2
= 675.22/2
= 337.61