Answer:
The service level for each component must be 97.91%
Explanation:
If we want a 90% confidence of starting on time, that means we need

As the probability of each component being ready is independent from the others, that means that the probability of the 5 components being ready is equal to multiply each probability:

The probability of being ready on time is equal to the service level (in fraction), and all 5 are equal so we can say:
![0.9=(\mbox{service level(in fraction)})^5\\\\\sqrt[5]{0.9} =\mbox{service level(in fraction)}=0.9791\\\mbox{In percentage}: \mbox{service level (in fraction)}*100 = 97.91\%](https://tex.z-dn.net/?f=0.9%3D%28%5Cmbox%7Bservice%20level%28in%20fraction%29%7D%29%5E5%5C%5C%5C%5C%5Csqrt%5B5%5D%7B0.9%7D%20%3D%5Cmbox%7Bservice%20level%28in%20fraction%29%7D%3D0.9791%5C%5C%5Cmbox%7BIn%20percentage%7D%3A%20%5Cmbox%7Bservice%20level%20%28in%20fraction%29%7D%2A100%20%3D%2097.91%5C%25)
Answer: Plot of
vs
would be linear with a slope of 4.
Explanation:
Given
Equation is 
Taking log both sides

It resembles with linear equation 
Here, slope of
vs
is 4.
Answer:
There is not going to be pressure build up in the system,that is isobaric process.
Explanation:
Assumptions to be made
1. No mass is gained or lost during the heating process.
2. There are no friction losses,so work is transmitted efficiently.
3. It was started the water in the drum and its surrounding have same temperature.
4. This system is closed,so there is no mass transfer across its boundaries.
Answer:
Between 35°– 45°
Explanation:
In the vertical position, Point the flame in the direction of travel. Keep the flame tip at the correct height above the base metal. An angle of 35°–45° should be maintained between the torch tip and the base metal. This angle may be varied up or down to heat or cool the weld pool if it is too narrow or too wide