By 272.7 degrees angle has planet Y rotated through during this time.
<h3 /><h3>What is Kepler's 3rd law?</h3>
The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.
Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that
(period X / period Y)^2 = (radius X / radius Y)^3
(period X / period Y)^2 = 2^3 = 8
take sq root
period X / period Y = √8 = 2.82≅ 3
this means it takes planet X 2.82≅ 3 times longer to go through one orbit... so planet Y travels 2.82≅ 3 times as far (in its orbit...) as planet X!
This means...
planet Y travels 3 * 90.9 = 272.7 degrees
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Answer:
Explanation:
given,
weight of the man = 680 N
weight of the woman = 500 N
mass of man = 
M_m = 69.4 Kg
mass of woman
= 
M_w = 51 Kg
ratio of man's kinetic energy Km to that of the woman Kw
momentum is same
Acceleration is the simply rate of change in velocity, how much faster or slower is the object changing speed with respect to time.
A = v/t = 5 km/hr/0.5 hr
5/1/2 = 5 • 2 = 10 km/hr^2.
This would be the acceleration.
Answer:
42.5 m/s
Explanation:
Given:
x₀ = 0 m
x = 62 m
y₀ = 80 m
y = 0 m
v₀ᵧ = 0 m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find: v
First, find the time it takes to land.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (80 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 4.04 s
Find the horizontal component vₓ:
x = x₀ + vₓ t − ½ aₓ t²
(62 m) = (0 m) + vₓ (4.04 s) − ½ (0 m/s²) (4.04 s)²
vₓ = 15.3 m/s
Find the vertical component vᵧ:
vᵧ = aᵧ t + v₀ᵧ
vᵧ = (-9.8 m/s²) (4.04 s) + (0 m/s)
vᵧ = -39.6 m/s
Find the speed using Pythagorean theorem:
v = √(vₓ² + vᵧ²)
v = √((15.3 m/s)² + (-39.6)²)
v = 42.5 m/s
The two elements are in the same period, with Element R the first element in the period and Element Q the last element.
