D=Vot+1/2at^2
In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2
acceleration=acceleration due to gravity=-9.8m/s^2
It falls - 22cm or -0.22m
We have - 0.22=1/2(-9.8)t^2
t^2=(-0.44)/(-9.8)
t=sqrt[0.44/9.8]
<span>Coefficient of static friction needs to be 1.1 or larger.
For this problem, we need to static friction to be at least as large as the centripetal acceleration that the car will experience. So let's get our formulas.
Centripetal acceleration:
F = mv^2/r
where
F = force
m = mass
v = velocity
r = radius of curve
Friction
F = mac
where
F = force
m = mass
a = gravitational acceleration
c = coefficient of friction
Since the frictional force has to be at least as large as the Centripetal force, let's set an inequality between them.
mv^2/r ≤ mac
v^2/r ≤ ac
v^2/(ar) ≤ c
Now let's convert km/h to a more convenient m/s.
104 km/h / 3600 s/h * 1000 m/km = 28.88888889 m/s
Let's substitute the known values into the inequality and calculate.
v^2/(ar) ≤ c
(28.88888889 m/s)^2/(9.8 m/s^2 * 78 m) ≤ c
834.5679012 m^2/s^2 / 764.4 m^2/s^2 ≤ c
1.091794743 ≤ c
Rounded to 2 significant figures gives a required coefficient of static friction of 1.1 or greater. This is a rather large value and indicates that the car is not at all likely to be capable of taking that curve at that speed. There are some things that can be done to mitigate the issue. Those being
1. Reduce the velocity.
2. Increase the normal force. Perhaps by aerodynamic means
3. Bank the curve.</span>
C. Abraham Maslow, wrote a paper about these needs in 1943 called, "A Theory of Human Motivation.
Answer:
K = 80.75 MeV
Explanation:
To calculate the kinetic energy of the antiproton we need to use conservation of energy:
<em>where : is the photon energy, : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>
Therefore the kinetic energy of the antiproton is:
<u>The proton mass is equal to the antiproton mass, so</u>:
Hence, the kinetic energy of the antiproton is 80.75 MeV.
I hope it helps you!
<span>The average acceleration of the car is given by:
</span>
<span>
where </span>
<span> is the initial velocity of the car, </span>
<span> is its final velocity and t is the time taken to attain the final speed. The car in the problem starts from rest, therefore its initial velocity is zero: </span>
<span>. The final velocity is </span>
<span>, while the time taken is
</span>
<span>
Therefore, the average acceleration of the car is
</span>
<span>
and the correct answer is C.</span>