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3 years ago

What is the best use of an atomic model to explain the charge of the particles in Thomason beans

1 answer:

5 0

An atom's negative particles are surrounded by positive matter, so the positive particles are easier to remove. Thomson's atom model is formed by positive and negative particles The positive particles are bigger than the negative，but the atom is still in equilibrium，this is possible because they have the same“density if you wanna call it like that。So，the properties of negative particles allow them to move free。On the other hand，bigger particles，don't have free moving like negative particles。That's why electrons（negative particles）are the definition of electricity，because they can move easily，although this movement depend on the material，metal are better to move in than wood or plastic.

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You observe lighting striking and then hear to sound 8 seconds later. The speed of sound in air is 340 m/s. How

Leto [7]

Answer:

2.72 Kilometers

Explanation:

8 × 340 m/s = 2720 m = 2.72 Kilometers

7 0

3 years ago

Using the law of conservation of angular momentum, estimate how fast a collapsed stellar core would spin if its initial spin rat

Nataly_w [17]

Answer:

$\omega_{f} = 1000000\,\frac{rev}{day}$

Explanation:

The law of conservation of angular momentum states that angular momentum remains constant when there is no external moment or forces applied to the system. Let assume that star can be modelled as an sphere, then:

$\frac{2}{5}\cdot M\cdot R_{o}^{2} \cdot \omega_{o} = \frac{2}{5}\cdot M\cdot R_{f}^{2} \cdot \omega_{f}$

The final angular speed is:

$\omega_{f} = \omega_{o}\cdot (\frac{R_{o}}{R_{f}})^{2}$

$\omega_{f} = (1\,\frac{rev}{day} )\cdot (\frac{10000\,km}{10\,km} )^{2}$

$\omega_{f} = 1000000\,\frac{rev}{day}$

3 0

3 years ago

Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An

Vikentia [17]

Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>

Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
Then, the equation connecting parallax and the distance in parsec can be written as,

$d=\frac{1}{P}$

We can say that,

$dP=constant.\\thus,\\d_1P_1=d_2P_2$

<h3>How to solve the problem?</h3>

We have given that,

$d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?$

Thus, we can find the distance in parsecs as,

$d_2=\frac{d_1P_1}{P_2} =23.46 parsecs$

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

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6 0

2 years ago

A spring has natural length 16 cm. A force of 3 N is required to holdthe spring compressed compressed to 11 cm. Find the amount

alexgriva [62]

Answer:

W = 0.012 J

Explanation:

For this exercise let's use Hooke's law to find the spring constant

F = K Δx

K = F / Δx

K = 3 / (0.16 - 0.11)

K = 60 N / m

Work is defined by

W = F. x = F x cos θ

in this case the force and the displacement go in the same direction therefore the angle is zero and the cosine is equal to 1

W = ∫ F dx

W = k ∫ x dx

we integrate

W = k x² / 2

W = ½ k x²

let's calculate

W = ½ 60 (0.19 -0.17)²

W = 0.012 J

8 0

3 years ago

A car is traveling west for 12 s its speed is 36.12 m/s in the same direction find the total distance the car traveled

ki77a [65]

<u>We are given:</u>

constant speed of the car (u) = 36.12 m/s

time in question (t) = 12 seconds

<u>Solving for the Distance and Displacement:</u>

from the second equation of motion:

s = ut + 1/2 at^2

since we have 0 acceleration:

s = ut

<em>replacing the variables</em>

s = 36.12 * 12

s = 433.44 m

Since the car is travelling in a straight line towards the same direction, it's Distance will be equal to its Displacement

Hence, both the Displacement and <u>Distance covered by the car is </u>

but since Displacement also has a direction vector along with it,

the <u>Displacement will be 433.44 m due west</u>

4 0

2 years ago