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Korolek [52]
3 years ago
14

What is the best use of an atomic model to explain the charge of the particles in Thomason beans

Physics
1 answer:
rosijanka [135]3 years ago
5 0
An atom's negative particles are surrounded by positive matter, so the positive particles are easier to remove. Thomson's atom model is formed by positive and negative particles The positive particles are bigger than the negative,but the atom is still in equilibrium,this is possible because they have the same“density if you wanna call it like that。So,the properties of negative particles allow them to move free。On the other hand,bigger particles,don't have free moving like negative particles。That's why electrons(negative particles)are the definition of electricity,because they can move easily,although this movement depend on the material,metal are better to move in than wood or plastic.
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According to research, college graduates are more likely to engage in all of the following EXCEPT:
Ksivusya [100]
Strange question. I’d say B)
7 0
3 years ago
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If a flea can jump straight up to a height of 0.410 m , what is its initial speed as it leaves the ground?
aivan3 [116]

Initial velocity = \(v_0\)

acceleration in the downward direction = -9.8 \(\frac {m}{s^2}\)

Final velocity at the highest point = 0

Maximum height reached = 0.410 m

Now, Using third equation of motion:

\(v^2 = {v_0}^{2} + 2aH

\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.410

\({v_0}^{2} = 2 \times 9.8 \times 0.410\)

\(v_0 = 2.834 \frac {m}{s}\)

Speed with which the flea jumps = \(2.834 \frac {m}{s}\)

4 0
3 years ago
What type of energy does an object gain as it is lifted at a constant speed?
marshall27 [118]
D. Gravitational potential
7 0
3 years ago
(d) Suppose you use a spring to launch a payload horizontally from the asteroid so that the payload ends up far from the asteroi
nydimaria [60]

Answer:

ks= 133.2 N/m

Explanation:

  • Assuming that we can neglect the gravitational potential energy of the mass, and that no other forces acting on the payload, total mechanical energy must be conserved.
  • This energy, at any time, is part elastic potential energy (stored in the spring) and part kinetic energy.
  • When the spring is initially compressed, the payload is at rest, so all energy is elastic potential.
  • Once the spring has returned to its natural state, all this elastic potential energy must have been turned into kinetic energy.
  • If the payload is launched horizontally, and no gravity is present,this means that its final speed will be horizontal only also, according to Newton's First Law.
  • So, we can write the following equation:

       \Delta U + \Delta K = 0 (1)

  • where ΔU = -1/2*k*(Δx)²  (2)
  • and ΔK = 1/2*m*v² (3)
  • Replacing in (2) and (3) by the givens, and simplifying, we can find the stiffness ks as follows:

       k_{s} =\frac{m*v^{2}}{\Delta x^{2}} = \frac{29 kg*(3m/s)^{2}}{(1.4m)^{2}} = 133.2 N/M (4)

5 0
3 years ago
Suppose a small quantity of radon gas, which has a half-life of 3.8 days, is accidentally released into the air in a laboratory.
Daniel [21]

Answer:

1 day

Explanation:

Let the safe level = x

The current level = x + 0.2x = 1.2 x

Thus,

Half life = 3.8 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{3.8}\ days^{-1}

The rate constant, k = 0.1824 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,

\frac {[A_t]}{[A_0]} = x / 1.2 x = 0.8333

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.8333=e^{-0.1824\times t}

t ≅ 1 day

<u>Lab must be vacated in 1 day.</u>

4 0
3 years ago
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