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Otrada [13]
3 years ago
6

A 230mg piece of gold is hammered into a sheet measuring 23cm x 17cm. What is the thickness of the sheet in meters? Density of g

old is 19.32g/cm3
Physics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

t= 0.0003 mm

Explanation:

Given that

mass ,m = 230 mg

m  = 0.23 g

Area ,A= 23 x 17 cm²

A= 391  cm²

Density ,ρ = 19.32 g/cm³

Lets take thinness of the sheet =  t cm

We know that

Mass = Density x Volume

m = ρ A t

Now by putting the values in the above equation we get

0.23 = 19.32 x 391 x t

t=\dfrac{0.23}{19.32\times 391}\ cm

t=0.000030 cm

t= 0.0003 mm

That is why the thickness of the sheet will be 0.0003 mm.

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The magnitude of the resultant force on the balloon is 374.13 N.

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The net vertical force on the balloon is calculated as follows;

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F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(247)^2 + (281)^2} \\\\F= 374.13 \ N

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