Answer:
1.2826 x 10^-13 m
Explanation:
Here, k be the kinetic energy and m be the mass
K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J
m = 1.67 x 10^-27 kg
λ = 1.2826 x 10^-13 m
A 230mg piece of gold is hammered into a sheet measuring 23cm x 17cm. What is the thickness of the sheet in meters? Density of g
1 answer:
Answer:
t= 0.0003 mm
Explanation:
Given that
mass ,m = 230 mg
m = 0.23 g
Area ,A= 23 x 17 cm²
A= 391 cm²
Density ,ρ = 19.32 g/cm³
Lets take thinness of the sheet = t cm
We know that
Mass = Density x Volume
m = ρ A t
Now by putting the values in the above equation we get
0.23 = 19.32 x 391 x t
t=0.000030 cm
t= 0.0003 mm
That is why the thickness of the sheet will be 0.0003 mm.
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Explanation:
It is given that,
Force applied to object,
Position,
(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :
or
The torque is acting in -z axis.
(a) The magnitude of torque is given by :
Hence, this is the required solution.
Answer:
56.86153 N
Explanation:
t =Time taken
F = Force
Power
Work done
The magnitude of the force that is exerted on the handle is 56.86153 N