Answer:
Explanation:
Chemical equation:
C₁₀H₈O + COCl₂  → C₁₁H₇O₂Cl + HCl
A. How many kilograms of C₁₁H₇O₂Cl form from 2.5×10*2 kg of naphthol?
Given data:
Mass of naphthol = 2.5 ×10² kg ( 250×1000 = 250000 g)
Mass of C₁₁H₇O₂Cl = ?
Solution:
Number of moles of naphthol = mass/ molar mass
Number of moles of naphthol = 250000 g/ 144.17 g/mol
Number of moles of naphthol = 1734.1 mol
Now we will compare the moles of naphthol with C₁₁H₇O₂Cl.
                      C₁₀H₈O       :         C₁₁H₇O₂Cl
                         1               :                1
                        1734.1         :             1734.1
Mass of C₁₁H₇O₂Cl:
Mass = number of moles × molar mass
Mass = 1734.1 mol × 206.5 g/mol
Mass = 358091.65 g
Gram to kilogram:
1 kg×358091.65 g/ 1000 g  = 358.1 kg
B. If 100. g of naphthol and 100. g of phosgene react, what is the theoretical yield of C11H7O2Cl?
Given data:
Mass of naphthol = 100 g
Mass of COCl₂ = 100 g
Theoretical yield of C₁₁H₇O₂Cl = ?
Solution:
Number of moles of naphthol:
Number of moles of naphthol = mass/ molar mass
Number of moles of naphthol = 100 g/ 144.17 g/mol
Number of moles of naphthol = 0.694 mol
Number of moles of phosgene:
Number of moles  = mass/ molar mass
Number of moles =  100 g/ 99 g/mol
Number of moles = 1.0 mol
Now we will compare the moles of naphthol and phosgene with C₁₁H₇O₂Cl.
                      C₁₀H₈O        :         C₁₁H₇O₂Cl
                         1                :                1
                        0.694        :              0.694
                     COCl₂          :             C₁₁H₇O₂Cl
                         1                :                1
                        1.0              :              1.0
The number of moles of C₁₁H₇O₂Cl produced by C₁₀H₈O are less so it will limiting reactant and limit the yield of  C₁₁H₇O₂Cl.
Mass of C₁₁H₇O₂Cl:
Mass = number of moles × molar mass
Mass =  0.694 mol × 206.5 g/mol
Mass = 143.3 g
Theoretical yield  =  143.3 g
C. If the actual yield of C11H7O2Cl in part b is 118 g, what is the percent yield?
Given data:
Actual yield of C₁₁H₇O₂Cl = 118 g
Theoretical yield = 143.3 g
Percent yield = ?
Solution:
Formula :
Percent yield = actual yield / theoretical yield × 100
Now we will put the values in formula.
Percent yield = 118 g/ 143.3 g × 100
Percent yield = 0.82 × 100
Percent yield = 82%