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Whitepunk [10]
3 years ago
15

True/False: Paraphrasing Einstein’s Theory of General Relativity, gravity "handprint" makes an "indentation" in the fabric of sp

ace and time. A. True B. False
Physics
1 answer:
Y_Kistochka [10]3 years ago
6 0
B.False

Einstein's vision of GR is NOT that somehow Gravity comes along and alters (indents?) some existing structure.
It is that Gravity (with its four possible sources) actually determines the entire global structure of Space-Time in which such sources are extant.
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A gas has a pressure of 220 kPa at a volume of 380K. At what temperature will the gas have a pressure of 256 kPa?
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The temperature will be the pressure of 130 ka
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A mass of 2.50 kg is in a gravitational field of 14.0 N/kg. What force acts on the mass?
Olenka [21]
To determine the force that acts on the mass, just multiply the mass by the gravitational field. Using the given data,
                             F = (2.50 kg)(14 N/kg) = 35 N
Therefore, the force that acts on the mass is equal to 35 N. 
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Max hears on the news that a total solar eclipse will be visible from his town in the coming week. Which of the following explai
viktelen [127]
I believe that the answer is A but correct me if i’m wrong
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3 years ago
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If the distance between two asteroids is halved, the gravitational force they exert on each other will
mamaluj [8]

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_{1} & m_{2}) and the distance between them (r) in the next way:

F=G\frac{m_{1}m_{2}}{r^{2}} (2)

Now if distance between asteroids is halved:

F_{2}=G\frac{m_{1}m_{2}}{(\frac{r}{2})^{2}}

F_{2}=G\frac{m_{1}m_{2}}{\frac{r^{2}}{4}}

F_{2}=G\frac{4m_{1}m_{2}}{r^{2}}=4G\frac{m_{1}m_{2}}{r^{2}}

Note that G\frac{m_{1}m_{2}}{r^{2}} because (1) is F so:

F_{2}=4F

It's four times greater!

3 0
3 years ago
Ultraviolet light having a wavelength of 97 nm strikes a metallic surface. Electrons leave the surface with speeds up to 3.48 ×
irga5000 [103]

Answer:

<h2><em>12.45eV</em></h2>

Explanation:

Before calculating the work function, we must know the formula for calculating the kinetic energy of an electron. The kinetic energy of an electron is the taken as the difference between incident photon energy and work function of a metal.

Mathematically, KE =  hf - Ф where;

h is the Planck constant

f is the frequency = c/λ

c is the speed of light

λ is the wavelength

Ф is the work function

The formula will become KE =  hc/λ - Ф. Making the work function the subject of the formula we have;

Ф = hc/λ - KE

Ф = hc/λ - 1/2mv²

Given parameters

c = 3*10⁸m/s

λ = 97*10⁻⁹m

velocity of the electron v = 3.48*10⁵m/s

h = 6.62607015 × 10⁻³⁴

m is the mass of the electron = 9.10938356 × 10⁻³¹kg

Substituting the given parameters into the formula Ф = hc/λ - 1/2mv²

Ф =  6.63 × 10⁻³⁴*3*10⁸/97*10⁻⁹ -  1/2*9.11*10⁻³¹(3.48*10⁵)²

Ф = 0.205*10⁻¹⁷ - 4.555*10⁻³¹*12.1104*10¹⁰

Ф = 0.205*10⁻¹⁷ - 55.163*10⁻²¹

Ф = 0.205*10⁻¹⁷ - 0.0055.163*10⁻¹⁷

Ф = 0.1995*10⁻¹⁷Joules

Since 1eV = 1.60218*10⁻¹⁹J

x = 0.1995*10⁻¹⁷Joules

cross multiply

x = 0.1995*10⁻¹⁷/1.60218*10⁻¹⁹

x = 0.1245*10²

x = 12.45eV

<em>Hence the work function of the metal in eV is 12.45eV</em>

6 0
3 years ago
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