Answer:
bruh
Explanation:
The purpose of this lab was to explore the different types of chemical reactions in this laboratory procedure. The question for this lab is, how does knowing the reactants and products help me classify a chemical reaction. In this experiment, I made observations of the reactants and the products. I used these observations to write the balanced chemical equations and to classify the reaction it made.
1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?
KE = [1/2]m(v^2) => v = √[2KE/m] = √[2*50,000joules/1000kg] = 10m/s
2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?
GPE = mgh => h = GPE / (mg) = 39,200 joules / (200kg * 9.8m/s^2) = 20m
3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?
KE = [1/2]m(v^2) => v = √ [ 2KE/m] = √[2*12.5 j / 1kg] = 5 m/s
GPE = mgh => h = GPE/(mg) = 98/(1kg*9.8m/s^2) = 10 m
Answer:
Celsius, Fahrenheit and Kelvin are the three common temperature scales.
Explanation:
Celsius, Fahrenheit and Kelvin are the three common temperature scales.
Answer:
CH₂O
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number.
Molecular formula:
Molecular formula shows the actual whole number ratio of elements present in compound.
Given molecular formula: C₆H₁₂O₆
Empirical formula = CH₂O
In molecular formula six moles of carbon six moles of oxygen and 12 moles of hydrogen are present.
To get the smallest whole number we divide the each number by 6 and we get CH₂O which is empirical formula of C₆H₁₂O₆.
Answer:
I can be a friend if u need
