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belka [17]
3 years ago
13

An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase

the temperature of the scuttle from 23.0 Celsius to 90
Chemistry
1 answer:
Serggg [28]3 years ago
4 0

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

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In which direction does the electric field point at a position directly east of positive charge.
butalik [34]

Answer:

The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.

Explanation:

4 0
3 years ago
Which common material is an example of a polyamide?
Vlad1618 [11]

Nylon 6,6 is a common example of a polyamide.

<em>Polyamides</em> are polymers that contain <em>repeating amide (-CO-NH-) linkages</em>.

The structure of Nylon 6,6 is  

[-NH-(CH_2)_6-<u>NH-CO</u>-(CH_2)_4-CO-]_<em>n</em>

where <em>n</em> is a large number.

The numbers in the name showow that there are six carbon atoms on either side of an amide linkage.

5 0
3 years ago
How many moles are in 1.505x10^24 molecules of surcrose
algol [13]

Answer:

2.499 moles of sucrose

Explanation:

Divide by Avogadro's number

5 0
3 years ago
Be sure to answer all parts. find the most acidic hydrogen in tert−butyl methyl ketone and write a chemical equation for the pro
sleet_krkn [62]
Those Hydrogen atoms which are present at alpha position to carbonyl group are mildly acidic in nature. When such acidic proton containing carbonyl compounds are treated with strong base, they yield enolates. The negative charge created on alpha carbon resonates and shifts to carbonyl oxygen resulting in formation of carbon double bond carbon.

In <span>tert−butyl methyl ketone there are two carbons at each alpha position. Among these two carbons only methyl carbon contains hydrogen atoms while the second one is bonded to further three carbons making it Quaternary carbon. The base abstracts proton from methyl group and enolate is formed. 

</span>tert−butyl methyl ketone in this case acts as acid, Hydroxyl ion acts as base, while the enolate generated is the conjugate base of <span>tert−butyl methyl ketone and Water produced is the conjugate acid of hydroxide ion.</span>

7 0
3 years ago
Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

\Delta T_{\text{f}} = K_{\text{f}} b

where b is the molal concentration

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}

If m is constant (5 g), then

n \propto \dfrac{1}{M}

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

7 0
3 years ago
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