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4 years ago

Make the following conversion. 0.0097 mg = _____ g

Physics

2 answers:

Cloud [144]4 years ago

8 0

Your answer should be 9.7 :)

Masteriza [31]4 years ago

8 0

Answer:

0.0000097 g

Explanation:

A Milligram is a unit of measuring a mass of a body in the metric system. It is equivalent to a thousandth of grams and mg is the symbol of a milligram.

Gram is the unit of mass of a substance in the metric system and it is represented as g.

Calculation

One thousand milligrams amount to one gram and the expression below can be used to convert mg to g;

gram = milligram ÷ 1000

so 0.0097 will amount to;

g = 0.0097 ÷ 1000

= 0.0000097 gram

Therefore 0.0097 mg is equivalent to 0.0000097 g

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What would a series circuit be used for?

igor_vitrenko [27]

Answer:

Explanation:

a series circuit would be an odd choice to power a battery or light a lamp when a direct would be much more efficient, and it's not converting types of energy, so C is the best possible answer

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3 years ago

What is the velocity of a jet plane that travels 48 meters East in 4 seconds?

soldier1979 [14.2K]

Answer:

the speed of a jet plane = v = 12 m/s

Explanation:

jet plane that travels 48 meters East in 4 seconds?

use the velocity as distance over time formula = v = d / t

where:

t = 4 sec

d = 48 m

plugin values into the formula

v = 48 m

4 sec

v = 12 m/s

therefore,

the speed of a jet plane = v = 12 m/s

8 0

4 years ago

An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper

dimulka [17.4K]

Answer:

The power output of this engine is $P = 17.5 W$

The the maximum (Carnot) efficiency is $\eta_c = 0.7424$

The actual efficiency of this engine is $\eta _a = 0.46$

Explanation:

From the question we are told that

The temperature of the hot reservoir is $T_h = 1250 \ K$

The temperature of the cold reservoir is $T_c = 322 \ K$

The energy absorbed from the hot reservoir is $E_h = 1.37 *10^{5} \ J$

The energy exhausts into cold reservoir is $E_c = 7.4 *10^{4} J$

The power output is mathematically represented as

$P = \frac{W}{t}$

Where t is the time taken which we will assume to be 1 hour = 3600 s

W is the workdone which is mathematically represented as

$W = E_h -E_c$

substituting values

$W = 63000 J$

$P = \frac{63000}{3600}$

$P = 17.5 W$

The Carnot efficiency is mathematically represented as

$\eta_c = 1 - \frac{T_c}{T_h}$

$\eta_c = 1 - \frac{322}{1250}$

$\eta_c = 0.7424$

The actual efficiency is mathematically represented as

$\eta _a = \frac{W}{E_h}$

substituting values

$\eta _a = \frac{63000}{1.37*10^{5}}$

$\eta _a = 0.46$

7 0

4 years ago

11. How can you determine if there is net force acting on an object?

Alisiya [41]

Answer:

Explanation:

Sum all the forces that are acting on the object and what ever the sum is, is what the net force is.

For example if there is a piece of wood sitting on a table the net force would be the sum of the forces that are acting on it, so the force of gravity (which is negative) + the normal force which would equal zero because they are the same value.

7 0

3 years ago

Aluminum rivets used in airplane construction are made slightly larger than the rivet holes and cooled by "dry ice" (solid CO2)

poizon [28]

Answer:

$\rm 4.554\ m m.$

Explanation:

Given:

Initial temperature, $\rm T_i=23.0\ ^\circ C=23 + 273.15 = 296.15\ K.$
Final temperature, $\rm T_f = -78.0\ ^\circ C = -78+273.15=195.15\ K.$
Diameter of the hole, $\rm d = 4.500\ m = 4.500\times 10^{-3}\ m.$
Expansion coefficient of the Aluminum, $\rm \alpha = 2.4\times 10^{-5}\ K^{-1}.$

Let the diameter of the rivet at $\rm T_i=23.0\ ^\circ C$ be $\rm d_o$ , such that,

$\rm d_o=d+\Delta d$

$\rm \Delta d$ is the elongation in the diameter of the rivet.

We know, The change in the diameter of the rivet is related with the change in temperature as:

$\rm \dfrac{\Delta d}{d_o}=\alpha \Delta T.$

where, $\rm \Delta T$ is the change in temperature = $\rm T_f-T_i=-195.15-296.15=-491.30\ K.$

Also, $\rm \Delta d=d_o-d.$

Using these values,

$\rm \dfrac{d_o-d}{d_o}=\alpha \Delta T\\1-\dfrac{d}{d_o}=\alpha \Delta T\\\dfrac{d}{d_o}=1+\alpha \Delta T\\\Rightarrow d_o = \dfrac{d}{1+\alpha \Delta T}\\=\dfrac{4.500\times 10^{-3}}{1+2.4\times10^{-5}\times (-491.30)}\\=4.554\times 10^{-3}\ m.\\=4.554\ m m.$

It is the required diameter of the rivet at $-78.0\ ^\circ C$ .

4 0

3 years ago