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13.What volume of hydrogen gas is produced when 92.4 g of sodium reacts completely according to the following reaction at 25 °C

Anastaziya [24]

Answer:

44.8L of hydrogen gas

Explanation:

The reaction expression is given as:

2Na + 2H₂O → 2NaOH + H₂

Given parameters:

Mass of sodium = 92.4g

Unknown:

Volume of hydrogen gas = ?

Solution:

To solve this problem:

1 mole of a substance at STP occupies a volume of 22.4L

Let us find the number of moles of the hydrogen gas;

Number of moles of Na = $\frac{mass}{molar mass}$

Molar mass of Na = 23g/mol

Number of moles = $\frac{92.4}{23}$ = 4.02mole

From the balanced reaction expression:

2 mole of Na will produce 1 mole of hydrogen gas

4.02 mole of Na will produce $\frac{4.02}{2}$ = 2mole of hydrogen gas

So

1 mole of a substance at STP occupies a volume of 22.4L

2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas

5 0

3 years ago

How many elements are in the periodic table?

gogolik [260]

There are 118 elements.

5 0

3 years ago

Read 2 more answers

Is it wierd if i think my step sis is thick

iren2701 [21]

Answer:

yes it is and sometimes it's not

8 0

2 years ago

Read 2 more answers

For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

7 0

3 years ago

Why does inhaled air need to be warmed filtered and moistened?

bearhunter [10]

The body has to do this to make sure and or to prevent damage to the delicate tissues that form the Respiratory System. This is important because Your body's organs, such as your heart and brain, need oxygen-rich blood to work well. (if it gets damaged by the Cold/Dry air you breath in on a daily)Respiratory failure also can occur if your lungs can't properly remove carbon dioxide (a waste gas) from your blood. Too much carbon dioxide in your blood can harm your body's organs.

Hopefully i helped ^.^ please mark brainly if its a possibility~

4 0

4 years ago