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Ket [755]
3 years ago
14

A person weighing 490N stands on a scale in an elevator. What does the scale read (normal force) when the elevator rises at a co

nstant velocity of 5 m/s?
Physics
1 answer:
Talja [164]3 years ago
6 0

Answer:

490 N

Explanation:

The elevator is rising at constant velocity: this means the acceleration of the system is zero, so according to Newton's second law, the net force on the system is also zero:

F_{net} = ma =0

There are two forces acting on the person standing on the scale:

- its weight, downward, whose magnitude is W=490 N

- The normal force of the scale on the person, N, which is upward

Since the net force must be zero, we have:

W-N=0

From which we find the normal force:

N=W=490 N

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Mademuasel [1]
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3 years ago
When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the
Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made X_R = X_G, so we need both equations:

For the red car:

X_R=\frac{a_R*t^2}{2}   With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

X_G=Xo + V_G*t   With V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s   and Xo = 200m

Since both positions will be the same:

\frac{a_R*t^2}{2}=Xo+V_G*t   Solving for t:

t1 = -5.8s  and   t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

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3 0
4 years ago
A hot-water stream at 80 ℃ enters a mixing chamber with a mass flow rate of 0.5 kg/s where it is mixed with a stream of cold wat
rewona [7]

Answer:

\dot{m_{2}}=0.865 kg/s

Explanation:

\dot{m_1}= 0.5kg/s

from steam tables , at 250 kPa, and at

T₁ = 80⁰C ⇒ h₁ = 335.02 kJ/kg

T₂ = 20⁰C⇒ h₂ = 83.915 kJ/kg

T₃ = 42⁰C ⇒ h₃ = 175.90 kJ/kg

we know

\dot{m_{in}}=\dot{m_{out}}

\dot{m_{1}}+\dot{m_{2}}=\dot{m_{3}}

according to energy balance equation

\dot{m_{in}}h_{in}=\dot{m_{out}}h_{out}

\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=\dot{m_{3}}h_{3}

\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=(\dot{m_{1}}+\dot{m_{2}})h_{3}\\(0.5\times 335.02)+(\dot{m_{2}}\times 83.915)=(0.5+\dot{m_{2}})175.90\\\dot{m_{2}}=0.865 kg/s

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