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kirill115 [55]
3 years ago
10

If an object with more mass is pushed with the same force as an object with less mass the object with more mass will accelerate?

Quickly? At the same rate? Or slowly?
Physics
2 answers:
Bezzdna [24]3 years ago
6 0

Now really ! You can do this one in your head.

Imagine ...

-- First, you push on a golf ball with one pound of force, and you watch to see how it picks up speed.

-- Then, you push on a school bus with one pound of force, and you watch to see how it picks up speed.

Now please, in your mind, which one speeds up easier ?

And don't tell me it's because one is white and the other one is yellow. It's the MASS !

expeople1 [14]3 years ago
5 0

Answer:

smaller acceleration, so lower change in velocity

Explanation:

To answer this question we examine the equation that relates mass with force and with acceleration: F=m*a.

Since we want to know what happens to the acceleration, we solve for it in the equation: a=\frac{F}{m}

Notice that we are asked what happens when the force applied is the same, but now it is applied in an object with more mass (M).

We therefore would have to compare our initial form:

a=\frac{F}{m} with the new one: a=\frac{F}{M} wher the denominator is a larger quantity, therefore making our division/quotient smaller. Then, we conclude that the acceleration will be smaller, and therefore the change in velocity of the object will be lower.

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musickatia [10]

Surface area and Mass

When a leaf falls, it is being accelerated by gravity to the ground but opposed by air resistance also the drag. The net force on a leaf will therefore be calculated by subtracting its weight of the leaf from its drag.

<h3>What is Air resistance ?</h3>

Air exerts a force known as air resistance. When an object is travelling through the air, the force works in the opposite direction.

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Explain which planets have seasons and why some planets have none at all.
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Answer:

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3 years ago
What is umax,c, the value of the maximum energy stored in the capacitor during one cycle?
TiliK225 [7]

1) 0.266 H

2) 0.040 J

3) 0.308\Omega

Explanation:

The diagram of the circuit is missing: find it in attachment.

1) What is L, the value of the inductance of the circuit?

For an RLC circuit, the resonant angular frequency is given by:

\omega=\frac{1}{\sqrt{LC}}

where

L is the inductance of the circuit

C is the capacitance of the circuit

In this problem, we have:

\omega=164 rad/s is the angular frequency of the generator, at which the circuit is in resonance

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

Therefore, solving for L, we find the inductance of the circuit:

L=\frac{1}{\omega^2 C}=\frac{1}{(164)^2(140\cdot 10^{-6})}=0.266 H

2) What is umax,c, the value of the maximum energy stored in the capacitor during one cycle

The maximum energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the maximum potential difference across the capacitor

Here we have:

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

V=24 V is the maximum voltage across the capacitor, which is the emf of the generator

Substituting, we find:

U=\frac{1}{2}(140\cdot 10^{-6})(24)^2=0.040 J

3) What is R, the value of the resistance of the circuit?

Here we want to find the resistance of the circuit.

The resistance of the circuit can be found by using Ohm's Law:

V=RI

where

V is the maximum voltage

R is the resistance

I is the maximum current

Here we have:

V = 24 V is the maximum voltage provided by the generator

I = 0.78 A is the maximum current in the circuit

Solving for R, we find the resistance:

R=\frac{V}{I}=\frac{0.24}{0.78}=0.308\Omega

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That's the definition of pressure ... force on a given area.

So when that force increases, it's an increase in pressure.
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