The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), butanoic a

Question

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The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), butanoic a

cid (C3H7COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity.

Chemistry

1 answer:

kati45 [8] · Answer 1 · 2022-02-16T05:54:45+03:00

Answer:

Magnesium chloride (MgCl₂) > Potassium bromide (KBr) > Butanoic acid (C₃H₇COOH) > Sugar (C₆H₁₂O₆) (Conductivity)

Explanation:

The given samples:

Magnesium chloride (MgCl₂):

It is a strong salt which dissociates 100% into 3 ions, 1 Mg²⁺ and 2 Cl⁻

Sugar (C₆H₁₂O₆):

It is a carbohydrate and will have 0% dissociation and thus, no ions.

Butanoic acid (C₃H₇COOH):

It is a carboxylic acid (weak acids) which partially dissociates.

Potassium bromide (KBr):

It is a strong salt which dissociates 100% into 2 ions, K⁺ and Br⁻.

Thus, Conductivity is directly proportional to the numbers of ions dissociated in the solution and hence will conduct more electricity.

So,

Magnesium chloride (MgCl₂) > Potassium bromide (KBr) > Butanoic acid (C₃H₇COOH) > Sugar (C₆H₁₂O₆) (Conductivity)