<u>Answer:</u> Oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
<u>Explanation:</u>
We are given a compound having formula
and we need to find the oxidation state of all the atoms in this compound. There are 2 different atoms present in this : Arsenic and Oxygen
Oxidation state is the number which is assigned to an element in a compound which represents the number of electrons lost or gained by an atom in a compound.
Oxidation state of oxygen as -2 which is same always. Now, to calculate the oxidation state of Arsenic, we take the oxidation state of it be 'x'
As, there are two arsenic atoms and three oxygen atoms, then:

Hence, oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
The first answer choice is correct: SF6 is a compound: it is a substance composed of more than one atom from different elements (sulfur and fluorine).
The second answer choice is incorrect: while SF6 is indeed a compound that contains seven atoms, those atoms are not identical since one is a sulfur atom and six are fluoride atoms.
The third answer choice is incorrect: SF6 is not an element because it can be separated chemically into simpler substances that are elements. All the atoms comprising an element must have the same number of protons (the same atomic number); sulfur and fluorine have different atomic numbers. There is no single nucleus in SF6; the S and six F atoms each has their own nucleus.
The fourth answer choice is incorrect; SF6 contains no carbon atom, and so wouldn’t meet a central criterion for an organic compound. Moreover, the formula SF6 indicates that the sulfur atom is not bonded to any other atom apart from fluorine atoms, and there are no bonding electrons left on the S. There is no plausible reason to think that a molecule with such weak intermolecular attractions as SF6 would form long chains of S atoms. Indeed, in standard conditions, SF6 is a gas.
Answer:
Shield Volcano . I've been their before
Explanation:
Answer:
C) Krypton is a noble gas, so it was difficult for chemists to find it, as though it was a secret.
Explanation: