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____ [38]
4 years ago
9

if a 2.0g sample of water at 5.0celcius absorbs 21.8Joules of energy, the temprature of the sample will be raised by

Chemistry
1 answer:
Cerrena [4.2K]4 years ago
8 0
You'd use the temperature change equation. The specific heat of water is always 4.18J/(g °C).
Equation to use: q=mCΔT

21.8=(2.0)(4.18)(Tf-5)
21.8=(8.36)(Tf-5)
21.8/8.36=Tf-5
2.61=Tf-5
2.61+5=Tf
Tf=7.61 °C

Since you want to know how many °C it raises, you wouldn't pay attention to the last 2 steps, however if you need to know the final temp, you want to go to the last step.
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Answer:

The answer to your question is below

Explanation:

1.-

a) Look for the mass number of Gold in the periodic table

Mass number = 197 g

Use proportions to answer this question

                          197 g of gold ------------- 6.023 x 10 ²³ atoms

                            4.64 g of gold ----------  x

                            x = (4.64 x 6.023 x 10²³) / 197

                           x = 1.42 x 10²² atoms

2.- mass of 4.12 x 10²⁴ molecules of glucose

Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)

                          = 72 + 12 + 96

                          = 180 g

             180 g of glucose ------------------- 6.023 x 10 ²³ molecules

                x                        -------------------  4.12 x 10 ²⁴ molecules

                x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³

               x = 1231.3 g of glucose                  

4 0
3 years ago
The enthalpy of vaporization for water is 40.67 kJ/mol and the enthalpy of fusion for water is
S_A_V [24]

Answer:

\Delta H_{dep}=-46.68kJ/mol

Explanation:

Hello!

In this case, since vaporization is the processes by which a liquid goes to the gas phase, fusion by which a solid goes to liquid and deposition by which a gas goes to solid; we infer that the following set up relates the enthalpies associated to each process:

\Delta H_{fus}+\Delta H_{vap}=-\Delta H_{dep}

Because deposition goes from a state with more energy to a state with less energy, therefore it is negative; in such a way, by plugging in we obtain:

\Delta H_{dep}=-(\Delta H_{fus}+\Delta H_{vap})\\\\\Delta H_{dep}=-(6.01kJ/mol+40.67kJ/mol)\\\\\Delta H_{dep}=-46.68kJ/mol

Best regards!

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This was clear chemical reaction. The Potassium Chlorate reacted with Oxygen in a combustion reaction to change the chemical structure so that it was able to react with Silver Nitrate.
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4 years ago
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