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Whitepunk [10]
4 years ago
5

How are rotation and day related?

Chemistry
1 answer:
Nadya [2.5K]4 years ago
3 0
When earth turns once it's a day
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With a well labeled diagram explain the stages of meiosis and mitosis​
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hope that helps

7 0
3 years ago
Magnesium (Mg) reacts with chlorine gas (Cl2) to produce magnesium chloride (MgCl2). How many grams of Mg will reacts with 2 mol
Rom4ik [11]
Mg   +   Cl₂ -----> MgCl₂
24g     1 mol


24g Mg ---- 1 mol Cl₂
Xg Mg ------ 2 mol Cl₂
X = 2×24
<u>X = 48g Mg</u>
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7 0
3 years ago
If you start with ten grams of reactants how many grams of product should you get
love history [14]
The sum of the masses of the reactants is equal to the sum of the masses of the products.
6 0
4 years ago
The compound Fe3CI is made of what?
sergeinik [125]

Answer:

nglos324 - fe3c. Iron carbide is an interstitial compound of iron and carbon with the composition Fe- 6.68 wt % Carbon. It is a brittle ceramic material and is produced in carbon steels or cast irons during pseudo-equilibrium cooling from above the eutectoid temperature (723 C).

Explanation:

4 0
4 years ago
Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso
Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

\Delta T_{f}= k_{f}m

where, \Delta T_{f} = depression in freezing point

k_{f} = molal depression constant    (20.0 ^{o}Ckg/mole)

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles  =\frac{given mass in g}{molar mass}

given mass  of biphenyl solute = 0.925 g

Molar mass of biphenyl  = 154.21 g/mol

Put the values,

number of moles of biphenyl =\frac{0.925 g}{154.21 g/mol}

= 0.0059 mole

Molality =\frac{number of moles of biphenyl solute}{mass of the solvent in kg}

Mass of cyclohexane solvent  = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane  = \frac{25.0}{1000}

= 0.025 kg

Now, put the values in the formula of molality:

Molality =\frac{0.0059 mole}{0.025 kg}

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg

= 4.72 ^{o}C

Now, \Delta T_{f} = T_{solvent} - T_{solution}

4.72 ^{o}C = 6.50^{o}C - T_{solution}

T_{solution} = 6.50^{o}C- 4.72 ^{o}C

= 1.78^{o}C

Hence, freezing point of the solution is 1.78^{o}C.



4 0
3 years ago
Read 2 more answers
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